PVAO=9500[(1-(1+0.078)^(-4))/0.078]
PVAO=31605.79
So the answer is 31606
Option C:
is the predicted population when 
Explanation:
The regression equation for an exponential data is 
Where x is the number of years and
y is the population
We need to determine the predicted population when 
The population x can be determined by substituting
in the equation 
Thus, we have,



Using the logarithmic definition
then 


Rounding off to the nearest whole number, we get,

Thus, the predicted population when
is 316
Hence, Option C is the correct answer.
Answer:
see explanation
Step-by-step explanation:
To determine which ordered pairs are solutions to the equation
Substitute the x and y values into the left side of the equation and if equal to the right side then they are a solution.
(- 1, - 6)
3(- 1) - 4(- 6) = - 3 + 24 = 21 = right side ← thus a solution
(- 3, 3)
3(- 3) - 4(3) = - 9 - 12 = - 21 ≠ 21 ← not a solution
(11, 3)
3(11) - 4(3) = 33 - 12 = 21 = right side ← thus a solution
(7, 0)
3(7) - 4(0) = 21 - 0 = 21 = right side ← thus a solution
The ordered pairs (- 1, - 6), (11, 3), (7, 0) are solutions to the equation
Answer:
C. Stacy
Step-by-step explanation:
One way to compare is to convert all the fractions into decimals
Rachel works 2/3 of her shift: Approximately= 0.667
Jose works 1/6: approx. = 0.1667
Damon works 4/5= 0.80
Stacy works 6/7: approx. = 0.8571
Now this makes it much easier to compare
And since 0.85714 (Stacy's shift) is the largest number, Stacy has completed the largest portion of her shift
Answer:
1) The linear regression model is y = -0.0348·x + 13.989
2) The correlation coefficient is -0.0725
3) The strength of the model is strong - association
Step-by-step explanation:
1)
X Y XY X²
27 13 351 729
65 12 780 4225
83 11 913 6889
109 10 1090 11881
142 9 1278 20164
175 8 1400 30625
∑ 601 63 5812 74513
From y = ax + b, we have

b = 1/n(∑y -a∑x) = 1/6(63 - (0.0348)×601) = 13.989
Therefore, the linear regression model is y = -0.0348·x + 13.989
2)
![r = \frac{n\sum xy - \sum x\sum y }{\sqrt{[n\sum x^{2}-\left (\sum x \right )^{2}] [n\sum y^{2}-\left (\sum y \right )^{2}]}} = \frac{6 \times 5812 - 601 \times 63}{\sqrt{[6 \times 74513-601^{2}] [6 \times 3969 - 63^2]} } = - 0.0725](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7Bn%5Csum%20xy%20-%20%5Csum%20x%5Csum%20y%20%7D%7B%5Csqrt%7B%5Bn%5Csum%20x%5E%7B2%7D-%5Cleft%20%28%5Csum%20x%20%20%5Cright%20%29%5E%7B2%7D%5D%20%5Bn%5Csum%20y%5E%7B2%7D-%5Cleft%20%28%5Csum%20y%20%20%5Cright%20%29%5E%7B2%7D%5D%7D%7D%20%20%3D%20%5Cfrac%7B6%20%5Ctimes%205812%20%20-%20601%20%5Ctimes%2063%7D%7B%5Csqrt%7B%5B6%20%5Ctimes%2074513-601%5E%7B2%7D%5D%20%5B6%20%20%5Ctimes%203969%20-%2063%5E2%5D%7D%20%7D%20%3D%20-%200.0725)
3) The strength is - association.