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2 years ago

Compute the following: Subscript 325 Baseline C Subscript 1 a. 325 b. 324 c. 1 d. 326

Mathematics

2 answers:

ozzi2 years ago

8 0

Answer:

325

Step-by-step explanation:

dem82 [27]2 years ago

8 0

Answer:

325

Step-by-step explanation:

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A certain type of thread is manufactured with a mean tensile strength of 78.3 kilograms and a standard deviation of 5.6 kilogram

azamat

Answer:

(a) The variance decreases.

(b) The variance increases.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The standard deviation of sample mean is inversely proportional to the sample size, n.

So, if n increases then the standard deviation will decrease and vice-versa.

(a)

The sample size is increased from 64 to 196.

As mentioned above, if the sample size is increased then the standard deviation will decrease.

So, on increasing the value of n from 64 to 196, the standard deviation of the sample mean will decrease.

The standard deviation of the sample mean for n = 64 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{64}}=0.7$

The standard deviation of the sample mean for n = 196 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4$

The standard deviation of the sample mean decreased from 0.7 to 0.4 when n is increased from 64 to 196.

Hence, the variance also decreases.

(b)

If the sample size is decreased then the standard deviation will increase.

So, on decreasing the value of n from 784 to 49, the standard deviation of the sample mean will increase.

The standard deviation of the sample mean for n = 784 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{784}}=0.2$

The standard deviation of the sample mean for n = 49 is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{49}}=0.8$

The standard deviation of the sample mean increased from 0.2 to 0.8 when n is decreased from 784 to 49.

Hence, the variance also increases.

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The Hoffman family has bought one pizza on Friday night every week for the last 10 years.

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Answer:520

Step-by-step explanation:.

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A sales representative can take one of 3 different routes from City Upper B to City Upper D and any one of 6 different routes fr

grigory [225]

Answer:

Step-by-step explanation:

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2 years ago

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One end of a 4ft iron rod is attached to the center of a pulley with radius of 0.5 ft. The other end is attached at a 40 degree

mr_godi [17]

We use the formula
L = rθ
where s is the arc length or the length of the wire
r is the distance from the center to the end of the rod
θ is the angle made by the rod with the wall

Substituting the values and converting the angle to radian measure
L = 4 (40°) (π/180°)
L = 2.79 feet

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2 years ago

Carla and Jonah are working together to determine if quadrilateral CDEF with coordinates C(2, 3), D(1, 2), E(4, 1), and F(5, 3)

mart [117]

Answer:

A. Carla is on the right track because she is finding the slopes of consecutive sides to check for perpendicular sides.

Step-by-step explanation:

Only adjacent sides can be perpendicular, so Jonah's approach of finding slopes of opposite sides cannot work.

Carla is on the right track; choice A.

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