the volume of a sphere whose diameter is 18 centimeters is 246 324 648 972 π cubic centimeters. if its diameter were reduced by
1 answer:
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Answer and Step-by-step explanation:
Data provided in the question
Mean = 1.1 hours per call =
R = Mean rate = 1.6 per eight hour day
=
= 5 per day
Based on the above information
a. The average number of customers is
= 151
b. The system utilization is
=
= 0.32
c. The amount of time required is
= 1 - system utilization
= 1 - 0.32
= 0.68
And, there is 8 hours per day
So, it would be
=
= 5.44 hours
d. Now the probability of two or more customers is
= 0.1024
Therefore we simply applied the above formulas
Answer:
Option B
Step-by-step explanation:
we know that
The area of the rectangle room, is equal to
where
L is the length
W is the width
we have
Remember that
1 yard= 3 feet
Convert yards to feet
The area is equal to
Answer:
Step-by-step explanation:
Before constructing bipartite graph, we need to have the responsibilities of each person sorted out first. I listed it in dash form for easy reading
Zamora
- planning,
- sales, marketing
- industry relations
Agraharam:
- planning
- development
Smith
- publicity,
- sales,
- industry relations
Chou
- planning,
- sales,
- industry relations
Macintyre
- planning,
- publicity,
- sales,
- industry relations
After we are done with that, we can start constructing the bipartite graph by making two column or two rows of group, one is for the person and the other is for responsibilities.
Later, we start match up each person to the responsibilities that assigned to them.
I attached the bipartite graph for this question as well.
Answer:
(a) Shown below.
(b) The probability that the first ball drawn is blue is 0.40.
(c) The probability that only white balls are drawn is 0.36.
Step-by-step explanation:
The balls in the urn are as follows:
Blue balls: B₁ and B₂
White balls: W₁, W₂ and W₃
It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.
(a)
The possible outcomes of selecting two balls are as follows:
B₁B₁ B₂B₁ W₁B₁ W₂B₁ W₃B₁
B₁B₂ B₂B₂ W₁B₂ W₂B₂ W₃B₂
B₁W₁ B₂W₁ W₁W₁ W₂W₁ W₃W₁
B₁W₂ B₂W₂ W₁W₂ W₂W₂ W₃W₂
B₁W₃ B₂W₃ W₁W₃ W₂W₃ W₃W₃
There are a total of N = 25 possible outcomes.
(b)
The sample space for selecting a blue ball first is:
S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}
n (S) = 10
Compute the probability that the first ball drawn is blue as follows:
Thus, the probability that the first ball drawn is blue is 0.40.
(c)
The sample space for selecting only white balls is:
X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}
n (X) = 9
Compute the probability that only white balls are drawn as follows:
Thus, the probability that only white balls are drawn is 0.36.