Answer: first option
Step-by-step explanation:
Let's make the following conversion:
40 inches to feet (Knowing that 1 feet=12 inches):

The formula for calculate the are of a rectangle is:

Where l is the lenght and w is the width.
Therefore, when you substitute values, you obtain the following result:

Answer:
<u>The measure of the arc CD = 64°</u>
Step-by-step explanation:
It is required to find the measure of the arc CD in degrees.
So, as shown at the graph
BE and AD are are diameters of circle P
And ∠APE is a right angle ⇒ ∠APE = 90°
So, BE⊥AD
And so, ∠BPE = 90° ⇒(1)
But it is given: ∠BPE = (33k-9)° ⇒(2)
From (1) and (2)
∴ 33k - 9 = 90
∴ 33k = 90 + 9 = 99
∴ k = 99/33 = 3
The measure of the arc CD = ∠CPD = 20k + 4
By substitution with k
<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>
Answer:
The volume of figure 1 is 11340 ft^3 greater than figure 2
Step-by-step explanation:
For rectangular prism, volume is
V = lenght x width x height
V = 36 x 21 x 18 = 13608 ft^3
For rectangular pyramid, volume is
V = (lenght x width x height) ÷ 3
V = (36 x 21 x 9) ÷3 = 6804/3 =2268 ft^3
Difference in volume = 11340 ft^3
When the concentration of a solution is expressed in weight percentages, that is just equal to the mass of solute over the mass of the total solution. For a solution weighing 210 grams, 5% of it is salt. That is equal to
210*0.05= 10.5 g salt
The rest of the amount, determined by difference, is the amount of solvent which is water.
water = 210-10.5 = 199.5 g salt
To solve for the new concentration, you add up 15 g to the already existing 10.5 g of salt in the solution. The water, on the other hand, remains constant.
Concentration = (15+10.5)/(210+15) = 0.1133 or 11.33%
Answer:
<em>5,598 cans are required to empty the vessel</em>
Step-by-step explanation:
The volume of a cylinder of radius r and height h is:

The volume of a box of dimensions X, Y, and Z is:
V=X.Y.Z
A cylinder of r=1.4 m and height h=1.5 is used to store vegetable ghee. It contains a volume of:


Converting to cubic cm:


The volume of each rectangular tin can is:


The number of cans required to empty the vessel is:

5,598 cans are required to empty the vessel