Answer:
Solve f(x)=6x-12 g(x)=5x+1 h(x)=x^2-4 (f+g)(x). f(x)=6x−12 f ( x ) = 6 x - 12 g(x)=5x+1 g ( x ) = 5 x + 1 h(x)=x2−4 h ( x ) = x 2 - 4 (f+g)(x) ( f + g ) ( x ). Evaluate f+g f + ...
Step-by-step explanation:
Solve f(x)=6x-12 g(x)=5x+1 h(x)=x^2-4 (f+g)(x). f(x)=6x−12 f ( x ) = 6 x - 12 g(x)=5x+1 g ( x ) = 5 x + 1 h(x)=x2−4 h ( x ) = x 2 - 4 (f+g)(x) ( f + g ) ( x ). Evaluate f+g f + ...
Given the bar graph above, the difference <span>in monthly electric cost appear to be great because of the choice of scale.
In scaling, the narrower the intervals of the axis, the larger the graph and the more highlighted the relative difference between the components of the graph.
Conversely, the wider the </span><span>the intervals of the axis, the smaller the graph and the less
highlighted the relative difference between the components of the graph.
Therefore, to make </span><span>the difference in monthly electric cost appear not to be as great</span>, we widden the intervals on the y-axis.
i.e. '<span>The interval on the y-axis could be changed to count by 20s.'</span>
Answer:
No, the two events "being in high school" and "GPA above 3.0" are not independent.
Step-by-step explanation:
If two events A,B are independent 
P(high school | above 3.0) = 
P(high school) = 
So,0.35 ≠ 0.6
Since P(high school | above 3.0) ≠ P(high school), the events "being in high school" and "GPA above 3.0" are not independent.
