answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrew [12]
2 years ago
14

Varia is studying abroad in Europe. She is required pay $3,500 (in US dollars) per year to the university, however, she must pay

in euros. How many euros can Varia expect to pay per month to the university? (Round to the nearest whole euro.)
0.7306 euros = 1 US dollar
Mathematics
1 answer:
sleet_krkn [62]2 years ago
7 0

Answer:

213 euros per month

Step-by-step explanation:

1dollar = 0.7306euros

thus $3,500 dollars can be found by a rule of three

dollar             euro

1             ⇒  0.7306

3500     ⇒        x

we find x as follows:

x=\frac{0.7306*3500}{1} = 2,557.1 euros

She will pay 2,557.1  euros per year.

Dividing between the 12 months of the year:

\frac{2,557.1}{12}=213.1

Rounding to the nearest whole euro she will pay 213 euros per month.

You might be interested in
Drag the tiles to the boxes to form correct pairs. Match the mathematicians to their descriptions.
velikii [3]
Euclid : known as father of geometry
Thales : greek philosopher who contributed 5 theorems of geometry
Pythagoras : had a theorem named after him
Hippocrates : compiled basic geometry facts into a textbook



6 0
2 years ago
Read 2 more answers
What is the estimate of 1374 x 6
timama [110]
Hey it is 1374 x6 8244

7 0
2 years ago
A tank contains 500 gallons of salt-free water. A brine containing 0.25 lb of salt per gallon runs into the tank at the rate of
Neporo4naja [7]

Answer:

0.0198 lbs per gallon

Step-by-step explanation:

amount of salt free water = 500 gallons

salt rate in = 1 gal/min

salt rate out = 1 gal/min

amount o salt in brine = 0.25 lb per gallon

Let the amount of salt in the tank be A(t) at any time t.

\frac{dA(t)}{dt} =salt rate in - salt rate out

salt rate in = 0.25 x 1 = 0.25

salt rate out = \frac{A(t)\times 1}{500}

The differential equation is given by

\frac{dA(t)}{dt} =1 - \frac{A(t)\times 1}{500}

where, A(0) = 0

So, the equation becomes

\frac{dA(t)}{dt} + \frac{A(t)}{500} = 1

Here the integrating factor is e^{\frac{dt}{500}}=e^{\frac{t}{500}}

The solution of the above differential equation is given by

A(t)\times e^{\frac{t}{500}} = \int e^{\frac{t}{500}}dt

A(t)\times e^{\frac{t}{500}} = 500\times e^{\frac{t}{500}}+C

where, C is the integrating constant.

A(t)=500+Ce^{-\frac{t}{500}}

Put, A(0) = 0

C = - 500

A(t)=500\left ( 1-e^{-\frac{t}{500} \right )

As concentration is defined as

Concentration = Quantity / Volume

C(t)=\frac{A(t)}{500}

C(t)=1-e^{\frac{-t}{500}}

Now concentration at t = 10 min

Put, t = 10 min

C(10)=1-e^{\frac{-10}{500}}

C (10) = 0.0198 lbs per gallon

Thus, teh concentration after 10 min is 0.0198 lbs per gallon.

7 0
2 years ago
The average time an individual reads online national news reports is 49 minutes. Assume the standard deviation is 16 minutes and
Olin [163]

Answer:

0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 49 minutes

Standard Deviation, σ = 16 minutes

We are given that the distribution of  time an individual reads is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(no more than 30 minutes)

P( x \leq 610) = P( z \leq \displaystyle\frac{30 - 49}{16}) = P(z \leq -1.1875)

Calculation the value from standard normal z table, we have,  

P(x \leq 30) = 0.118 = 11.8\%

0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.

3 0
2 years ago
A random sample of house sizes in major city has a sample mean of x¯=1204.9 sq ft and sample standard deviation of s=124.6 sq ft
Svet_ta [14]

Answer: 95%

Step-by-step explanation:

The Empirical rule says that about 68% of the data is within one standard deviation of the mean; about 95% of the data is within two standard deviations of the mean ; about 99.7% of the data is within three standard deviations of the mean.

Given : Sample mean : \overline{x}=1204.9\text{ sq.ft.}

Standard deviation: s=124.6\text{ sq. ft.}

To find the percentage of house sizes that lie between 955.7 and 1454.1 sq ft.

We can write it as 955.7=1204.9-249.2=1204.9-2(124.6)

and 1454.1=1204.9+249.2=1204.9+2(124.6)

Thus, 955.7 is 2 standard deviations left from the means and 1454.1 is 2 deviations right from the mean.

Then by empirical rule , about 95% of house sizes that lie between 955.7 and 1454.1 sq ft .

6 0
2 years ago
Other questions:
  • Which represents the solution set to the inequality 5.1(3 + 2.2x) > –14.25 – 6(1.7x + 4)?
    8·2 answers
  • Dion flips a coin 20 times and records if it comes up heads. If getting heads is a success, what is the probability of a success
    8·2 answers
  • The dimensions of a rectangular bin are consecutive integers. If the volume of the bin is 4896 cubic inches, what are the dimens
    12·2 answers
  • The decimal equivalent of the fraction 2/15 is____. The number of digits that should be overlined is___.
    15·2 answers
  • 6x^2-2.4=0<br><br> show all answers<br><br> I need the answer desperatly
    11·1 answer
  • Find the hcf of 144 and 180. if it is expressed in the form 13m-3, find the value of m​
    5·2 answers
  • Analyze the graph of the cube root function shown on the right to determine the transformations of the parent function. Then, de
    15·2 answers
  • Write an equation of a circle whose center is (-5,4) and whose diameter is 12
    6·1 answer
  • Which are vertical angles? Check all that apply. ∠EAB and ∠BAC ∠EAB and ∠CAD ∠CAD and ∠FAE ∠CAB and ∠DAE ∠DAC and ∠DAE
    14·2 answers
  • In RST, RS = 7, RT = 10, and ST = 8. Which angle of RST has the smallest measure? A T BCANNT BE DETERMINDED C R D S
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!