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Brilliant_brown [7]
2 years ago
8

An ancient Chinese candle clock tells the amount of time that has passed by the amount of wax that has been melted off the candl

e. Each candle is divided into 12 sections, marked 1 inch apart. It takes 4 hours for each candle to completely melt, after which a new candle is lit. If two candles have completely melted and one candle has melted 4 in, how many minutes have passed since the first candle was lit?
Mathematics
2 answers:
rjkz [21]2 years ago
8 0
Two candles=8 hours=8*60=480 minutes
4 inch is 4/12 of a candle, 4/12 of 4 hours=16/12=4/3 hours=80 minutes
so the total minutes are 480+80=560 
rosijanka [135]2 years ago
4 0

Answer:

480+80=560

If a colored candle and a white candle are burned at the same time for an hour, then the colored candle will burn faster, because it has more chemicals than the white candle.

You might be interested in
Bill and Pete shared 1/2 of a cake. Bill got to eat twice as much cake as Pete. What fraction of the whole cake did Bill eat?
KatRina [158]

Answer:

Step-by-step explanation:

Total cake shared=1/2

Pete share=x

Bill= twice as much as Pete

=2x

Pete's share+ Bill's share=total share

x+2x=1/2

3x=1/2

x=1/2÷3

x=1/2×1/3

=1/6

Pete's share=x=1/6

Bill's share=2x

=2(1/6)

=2/6

=1/3

3 0
2 years ago
For each system of equations, drag the true statement about its solution set to the box under the system?
natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

 of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

   coefficients of x and y are the same and the numerical terms

   are the same

- The system of equation has one solution if at least one of the

  coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

  numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0
2 years ago
If 15% of the customer's total is $22.05, then the customer's total is
Harrizon [31]

<u>Answer</u>:  If 15% of the customer's total is $22.05, then the customer's total is <u>$147</u>.

<u>Step-by-step explanation</u>:

Let x be the customer's total amount.

It is given that 15% of the customer's total = $22.05

⇒15% of x= $22.05

\Rightarrow0.15x=\$22.05\\\\\text{Divide 0.15 on both sides, we get}\22.05\\\\\Rightarrow x=\frac{22.05}{0.15}\\\\\Rightarrow x=\$147

Therefore, If 15% of the customer's total is $22.05, then the customer's total is <u>$147</u>.

6 0
2 years ago
Read 2 more answers
Traffic speed: The mean speed for a sample of cars at a certain intersection was kilometers per hour with a standard deviation o
aliina [53]

Answer:

Step-by-step explanation:

Hello!

X₁: speed of a motorcycle at a certain intersection.

n₁= 135

X[bar]₁= 33.99 km/h

S₁= 4.02 km/h

X₂: speed of a car at a certain intersection.

n₂= 42 cars

X[bar]₂= 26.56 km/h

S₂= 2.45 km/h

Assuming

X₁~N(μ₁; σ₁²)

X₂~N(μ₂; σ₂²)

and σ₁² = σ₂²

<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>

The parameter of interest is μ₁-μ₂

(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2} * Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }

t_{n_1+n_2-2;1-\alpha /2}= t_{175; 0.95}= 1.654

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{134*16.1604+41*6.0025}{135+42-2} } = 3.71

[(33.99-26.56) ± 1.654 *(3.71*\sqrt{\frac{1}{135} +\frac{1}{42} })]

[6.345; 8.514]= [6.35; 8.51]km/h

<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>

t_{n_1+n_2-2;1-\alpha /2}= t_{25; 0.99}= 2.485

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{11*(43.48)^2+14*(21.60)^2}{12+15-2} } = 33.06

[(475.12-321.34) ± 2.485 *(33.06*\sqrt{\frac{1}{12} +\frac{1}{15} })]

[121.96; 185.60]

I hope this helps!

3 0
2 years ago
John needs 13 bottles of water from the store. john can only carry 3 at a time. what's the minimum number of trips john needs to
Lostsunrise [7]
The minimum amount of trips would be 5. This is because in one trip he can only carry 3, so you would take 5 times 3. You may think it should be 4 trips, but 12 is 1 short of 13,so you would have to make one extra trip to get all 13 bottles.
4 0
2 years ago
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