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frozen [14]
2 years ago
7

A person invests 6500 dollars in a bank. The bank pays 7% interest compounded

Mathematics
1 answer:
Inessa [10]2 years ago
6 0

Answer:

t=16.2 years

Step-by-step explanation:

A=p(1+r/n)^nt

A=$20100

P=$6500

r=7%=0.07

n=4

t=?

t=ln(A/P)/n {ln(1+r/n)}

=ln(20100/6500) / 4{ln(1+0.07/4)}

=ln(3.0923)/4{ln(1+0.0175)}

=ln(3.0923)/4{ln(1.0175)}

=1.1289/4(0.0174)

=1.1289/0.0696

=16.23

To the nearest tenth

t=16.2 years

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For the angles α and β in the figures, find cos(α + β)?
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Answer:

\cos(\alpha +\beta)=\frac{2}{3}(1-\frac{\sqrt{5}}{5})

Step-by-step explanation:

Let the hypotenuse of the smaller triangle be h units.

Then; from the Pythagoras Theorem.

h^2=4^2+2^2

h^2=16+4

h^2=20

h=\sqrt{20}

h=2\sqrt{5}

From the smaller triangle;

\cos (\alpha)=\frac{4}{2\sqrt{5} }=\frac{2}{\sqrt{5} } and \sin(\alpha)=\frac{2}{2\sqrt{5} }=\frac{1}{\sqrt{5} }

From the second triangle, let the other other shorter leg of the second triangle be s units.

Then;

s^2+4^2=6^2

s^2+16=36

s^2=36-16

s^2=20

s=\sqrt{20}

s=2\sqrt{5}

\cos(\beta)=\frac{2\sqrt{5} }{6}=\frac{\sqrt{5} }{3}

and

\sin(\beta)=\frac{4}{6}=\frac{2}{3}

We now use the double angle property;

\cos(\alpha +\beta)=\cos(\alpha)\cos(\beta) -\sin(\alpha)\sin(\beta)

we plug in the values to obtain;

\cos(\alpha +\beta)=\frac{2}{\sqrt{5} }\times \frac{\sqrt{5} }{3}-\frac{1}{\sqrt{5} }\times \frac{2}{3}

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The differential equation y′′=0 has one of the following two parameter families as its general solution: yyyy=C1ex+C2e−x=C1cos(x
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Answer:

y_c = 2 + 10*x

Step-by-step explanation:

Given:

                                                y'' = 0

Find:

- The solution to ODE such that y(0) = 2, y'(0) = 10

Solution:

- Assuming a solution y = Ce^(mt)

So,                                y' = C*me^(mt)

                                    y'' = C*m^2e^(mt)

- Back substitute into given ODE, we get:

                                    y'' = C*m^2e^(mt) = 0

                                    e^(mt) can not be equal to zero

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- The complimentary function for repeated roots is:

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                                    y_c = C1 + C2*x  

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                                    C1 = 2

-Evaluate @ y'(0) = 10

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Hence,                         y_c = 2 + 10*x

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