Answer:
Step-by-step explanation:
-12+5x=-24+x
4x=-12
x=-3
Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
There are three questions related to this problem.
First, the probability of the mail will arrive after 2:30
PM
<span>Find the z-score of 2:30 which is 30 minutes after 2:00.</span>
<span>
z(2:30) = (2:30 – 2:00)/15 = -30/15 = -2</span>
<span>
P(x < 2:30) = P(z<-2) = 0.0228</span>
<span>
</span>
Second, the probability of the mail will arrive at 1:36
PM
<span>Find the z-score of 1:36 which is 24 minutes before 2:00.</span>
<span>
z(1:36) = (1:36 – 2:00)/15 = -24/15 = -1.6</span>
<span>
P(x < 1:36) = P(z<-1.6) = 0.0548</span>
Lastly, the probability of the mail will arrive between 1:48
PM and 2:09 PM
Find the z-score of 1:46 and 2:09 PM which will result to
a z value of 0.034599
<span>P(1:48 < x < 2:09) = P(z<0.034599) = 0.5138</span>
Step-by-step explanation:
A leap year occurs every 4th year.
So, 1875 - 1700 = 175
Now let us divide 175 by 4

So, 43 leap years occur between the years 1700 and 1875.