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Zolol [24]
2 years ago
15

Typographers measure font sizes in units called points. One point is equal to 1/72 inches. Esmeralda is typing a research paper

on her computer. She wants the text on the title page to be 1/2 inch tall. What font size should she use?
Mathematics
2 answers:
Amiraneli [1.4K]2 years ago
4 0

Answer:

The size of the font would be 36

Step-by-step explanation:

The size of a font can be expressed as follows:

font size = (height of the font in inches)/(point)

A point has a size of 1/72 inches, If Esmeralda wants the texto on the title to be 1/2inch tall, we could use the formula:

font size = \frac{\frac{1}{2}}{\frac{1}{72}}\\\\font size = \frac{1*72}{2*1} \\\\font size = 36

kakasveta [241]2 years ago
3 0
She should use 36 points font size
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Which term describes a time period marked by a change that begins a new period of development? century decade era millennium
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Answer:

Era

Step-by-step explanation:

Century, Decade and Millennium have something in common and that which they have in common is that they are all measurement of time.

The keyword measurement implies that they are units of time just like seconds, minutes, hours, etc.

Century -> 100 years

Decade -> 10 years

Millennium -> 1000 years

However, era is used to describe events in history;

Take for instance; the era of the first generation of computer;

So, from the list of given options; Era best answers the question

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In quadrilateral RSTU, RS = 60 mm, ST = 60 mm, TU = 112 mm, and UR = 112 mm.
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A. factor 4

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Which inequality shows that Jerome wants to have read at least 85 pages by the end of Friday
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Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −
Korolek [52]

The vector field

\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k

has curl

\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath

Parameterize S by

\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k

where

\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}

with 0\le u\le3 and 0\le v\le2\pi.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k

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\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

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\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0

4 0
2 years ago
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