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2 years ago

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8. You realize that, despite what you expected, the soda actually tastes different depending on which flavor you choose first, s

econd, etc. With this in mind, how many different sodas can you make?

1 answer:

patriot [66]2 years ago

8 0

More background info?

You might be interested in

3 x 1/6 in simplest form

Travka [436]

Im not sure but i thing its 0.5 or 1/2
cause if you take (3/1)*(1/6) that's what you will get
also you had to make 3 as a fraction so you would put the denominator as 1 so if you divide 1 and 3 you would still get the whole number as 3

6 0

2 years ago

Read 2 more answers

Budget planners in two towns, Alphaville and Betaville, developed models to determine the budget surplus (in dollars) for a year

kramer

Answer:

(a) $-3x^2+150x-10000$

(b) $-\$16,863,760,000$

Step-by-step explanation:

Alphaville's Budget Surplus Model is $-2x^2+ 500x$

Betaville's Budget Surplus Model is $x^2- 100x + 10000.$

We want to determine the expression that shows how much greater Alphaville’s annual budget surplus is than Betaville’s for a particular amount of tax revenue.

To do this, we subtract Betaville's Model from Alphaville's model.

$-2x^2+ 500x-(x^2- 100x + 10000)\\$

Opening the brackets

$-2x^2+ 500x-x^2+100x - 10000\\$

Collect like terms and simplify

$-2x^2-x^2+100x + 500x- 10000\\=-3x^2+150x-10000$

The expression that shows how much greater Alphaville's Budget is:

$-3x^2+150x-10000$

(b) If the tax revenue that year in each town is $75,000

We want to evaluate the expression derived above when the tax revenue that year in each town is $75,000 i.e.at x=75000

$-3x^2+150x-10000\\=-3(75000)^2+150(75000)-10000\\=-\$16,863,760,000$

3 0

2 years ago

10 times as many as 1 ten is ______ tens.

anyanavicka [17]

Same 10 tens I guess

5 0

2 years ago

Solve the inequality. c – 5 ≤ 6

Vilka [71]

Hello There!

Follow through:
c - 5 $\leq$ 6
Add 5 to both sides:
c - 5 + 5 ≤ 6 + 5
Simplify:
c ≤ 11

C is smaller than or equal to 11.

Hope This Helps You!
Good Luck :)

- Hannah ❤

3 0

2 years ago

Read 2 more answers

For circle O, and m∠ABC = 55°. In the figure, ∠_____ and ∠____ have measures equal to 35°.

luda_lava [24]

Answer:

In the figure ∠ABO and ∠BCO have measures equal to 35°.

Step-by-step explanation:

<u><em>The complete question is</em></u>

For circle O, m CD=125° and m∠ABC = 55°

In the figure<____, (AOB, ABO, BOA) and <_____ (BCO, OBC,BOC) have measures equal to 35°

The picture in the attached figure

step 1

Find the measure of angle COB

we know that

$m\angle COB=arc\ CD$ ----> by central angle

we have

$arc\ CD=125^o$

therefore

$m\angle COB=125^o$

step 2

we know that

AB is a tangent to the circle O at point A

so

ABC and ABO are right triangles

In the right triangle ABC

Find the measure of angle BCA

Remember that

$m\angle BCA+m\angle\ ABC=90^o$ ---> by complementary angles in a right triangle

we have

$m\angle ABC=55^o$

substitute

$m\angle BCA+55^o=90^o$

$m\angle BCA=90^o-55^o=35^o\\$

step 3

In the triangle BCO

Find the measure of angle CBO

we know that

$m\angle CBO+m\angle COB+m\angle BCO=180^o$ ---> the sum of the interior angles in any triangle must be equal to 180 degrees

we have

$m\angle COB=125^o$

$m\angle BCO=m\angle BCA=35^o$ -----> have measure equal to 35 degrees

substitute

$m\angle CBO+125^o+35^o=180^o$

$m\angle CBO=180^o-160^o=20^o$

step 4

Find the measure of angle ABO

In the right triangle ABO

we know that

$m\angle ABC=m\angle CBO+m\angle ABO$ ----> by angle addition postulate

we have

$m\angle ABC=55^o$

$m\angle CBO=20^o$

substitute

$55^o=20^o+m\angle ABO$

$m\angle ABO=55^o-20^o=35^o$ ----> have measure equal to 35 degrees

therefore

In the figure ∠ABO and ∠BCO have measures equal to 35°.

3 0

2 years ago