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lakkis [162]
2 years ago
11

A business bought some compact cars that cost $15,000 each, and some full–sized cars, that cost $23,000 each. A total of 20 cars

were bought, for $372,000. How many compact cars did the business buy?
Mathematics
1 answer:
IceJOKER [234]2 years ago
3 0
<span>Let Y be the number of compact cars and 20 - Y be the number of full-sized car. If the total cost of 20 cars is $372, 000. Then we have: (Cost of compact car * number of compact car)+ (cost of full-sized car * number of full-sized car). So we have (15, 000 * Y) + (23, 000 * (20 -Y)) = 372, 000. Multiplying the expression, we have; 15, 000Y + 460, 000 - 23000Y = 372, 000. 15000Y - 23000Y = 372, 000 - 460, 000. -8000Y = - 88, 000. Hence Y = 11. Hence 11 compact cars were bought.</span>
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Answer:

Part a) The exterior surface area is equal to 160\ ft^{2}

Part b) The volume is equal to 240\ ft^{3}

Part c) The volume water left in the trough will be 84\ ft^{3}

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

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<em>Find the area of two rectangles</em>

A=2[12*5]=120\ ft^{2}

<em>Find the area of two trapezoids</em>

A=2[\frac{1}{2}(8+2)h]

Applying Pythagoras theorem calculate the height h

h^{2}=5^{2}-3^{2}

h^{2}=16

h=4\ ft

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A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}

The exterior surface area is equal to

120\ ft^{2}+40\ ft^{2}=160\ ft^{2}

Part b) Find the volume

We know that

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=20\ ft^{2}

L=12\ ft

substitute

V=20(12)=240\ ft^{3}

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

A=\frac{1}{2}(5+2)(2)=7\ ft^{2}

<em>step 2</em>

Find the volume

The volume is equal to

V=BL

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L is the length of the trough

we have

B=7\ ft^{2}

L=12\ ft

substitute

V=7(12)=84\ ft^{3}

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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(f) The probability that the machine either overfill or underfills is

P(C∪B)=P(C)+P(B)=0.052+0.008=0.06 because C and B are mutually exclusive events.

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