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kvv77 [185]
2 years ago
10

A carton contains 1 3/4 quarts of ice cream. One serving is 1/5 of a quart. How many servings of ice cream are in the bucket? A)

4/35 B)7/20 C)2 6/7 D)7 1/4 E)8 3/4
Mathematics
1 answer:
aalyn [17]2 years ago
4 0
(1 3/4) / (1/5) =
(7/4) / (1/5) =
7/4 * 5/1 =
35/4 or 8 3/4 <===
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What is the following product? Assume x greater-than-or-equal-to 0 (4 x StartRoot 5 x squared EndRoot + 2 x squared StartRoot 6
makvit [3.9K]

Answer:

D

Step-by-step explanation:

(4x√5x^2 +2x^2√6)^2 

remove the last ^2 by multiplying the parenthesis by each other:

(4x√5x^2 +2x^2√6) * (4x√5x^2 +2x^2√6)

 use FOIL & distribute :

4x√5x(4x√5x +2x^2√6) +2x^2√6(4x√5x +2x^2√6)

apply the distributive property once more:

4x^2√5(4x^2√5)+ 4x^2√5(2x^2√6) + (2x^2√6(4x^2√5) +2x^2√6(2x^2√6)

remove parenthesis and combine like terms to get:

104x^4+16x^4√30

 answer is D

4 0
2 years ago
Read 2 more answers
Show that the Fibonacci numbers satisfy the recurrence relation fn = 5fn−4 + 3fn−5 for n = 5, 6, 7, . . . , together with the in
Sonja [21]

Answer with step-by-step explanation:

We are given that the recurrence relation

f_n=5f_{n-4}+3f_{n-5}

for n=5,6,7,..

Initial condition

f_0=0,f_1=1,f_2=1,f_3=2,f_4=3

We have to show that Fibonacci numbers satisfies the recurrence relation.

The recurrence relation of Fibonacci numbers

f_n=f_{n-1}+f_{n-2},f_0=0,f_1=1

Apply this

f_n=(f_{n-2}+f_{n-3})+f_{n-2}=2f_{n-2}+f_{n-3}

f_n=2(f_{n-3}+f_{n-4})+f_{n-3}=3f_{n-3}+2f_{n-4}

f_n=3(f_{n-4}+f_{n-5})+2f_{n-4}=5f_{n-4}+3f_{n-5}

Substitute n=2

f_2=f_1+f_0=1+0=1

f_3=f_2+f_1=1+1=2

f_4=f_3+f_2=2+1=3

Hence, the Fibonacci numbers satisfied the given recurrence relation .

Now, we have to show that f_{5n} is divisible by 5 for n=1,2,3,..

Now replace n by 5n

f_{5n}=5f_{5n-4}+3f_{5n-5}

Apply induction

Substitute n=1

f_5=5f_1+3f_0=5+0=5

It is true for n=1

Suppose it is true for n=k

f_{5k}=5f_{5k-4}+3f_{5k-5} is divisible 5

Let f_{5k}=5q

Now, we shall prove that for n=k+1 is true

f_{5k+5}=5f_{5k+5-4}+3f_{5k+5-5}=5f_{5k+1}+3f_{5k}=5f_{5k+1}+3(5q)

f_{5k+5}=5(f_{5k+1}+3q)

It is multiple of 5 .Therefore, it is divisible by 5.

It is true for n=k+1

Hence, the f_{5n} is divisible by 5 for n=1,2,3,..

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2 years ago
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Dmitrij [34]

Answer:

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2 years ago
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44 students completed some homework and the histogram shows information about the times taken. Work out an estimate of the inter
Vilka [71]

Answer:

q1=11

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Step-by-step explanation:

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25 % of 44 = 25/100 * 44= 0.25 *44 = 11

So the first quartile lies at 11.

Similarly the third quartile lies at the 75 % of the numbers of the data set . So

75 % of 44 = 75/100 * 44= 0.75 *44 = 33

So the third quartile lies at 33.

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Answer:

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Step-by-step explanation:

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0.20409323479 x 100 = 20.409323479

round it

= 20.41%

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2 years ago
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