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DiKsa [7]
2 years ago
8

Forty students are in the science club. Of those, 45% are girls. This percent increases to 56% after new girls join the club. Ho

w many new girls join?
Mathematics
1 answer:
Gekata [30.6K]2 years ago
6 0
Around 22-23 create a function and input these to find the exact

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A pair of socks costs $2.50 originally. The price is reduced to $1.75. What is the percent change?
telo118 [61]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

% change = difference / original x 100

% change = (0.75 / 2.5) x 100

% change = 30%

It was a 30% change

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6 0
1 year ago
Read 2 more answers
Two kilograms of ground cinnamon is packaged into bags containing 38 g each. There will also be some cinnamon left over. How man
Troyanec [42]
I think about 52 bags
2 kilometers = 2,000 grams
2, 000/ 38 = 52. repeated decimal(which would be the amount leftover)
I believe the answer would be 52 bags.

5 0
2 years ago
Read 2 more answers
Hard times In June 2010, a random poll of 800 working men found that 9% had taken on a second job to help pay the bills. (www.ca
Phoenix [80]

Answer:

a) The 95% confidence interval would be given (0.0702;0.1098).

We can conclude that the true population proportion at 95% of confidence is between (0.0702;0.1098)

b) Since the confidence interval NOT contains the value 0.06 we  have anough evidence to reject the claim at 5% of significance.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest  

\hat p =0.09 represent the estimated proportion for the sample  

n=800 is the sample size required  

z represent the critical value for the margin of error  

Confidence =0.95 or 95%

Part a

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval would be given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

The margin of error is given by :

Me=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

Me=1.96 \sqrt{\frac{0.09(1-0.09)}{800}}=0.0198

And replacing into the confidence interval formula we got:  

0.09 - 1.96 \sqrt{\frac{0.09(1-0.09)}{800}}=0.0702  

0.09 + 1.96 \sqrt{\frac{0.108(1-0.09)}{800}}=0.1098  

And the 95% confidence interval would be given (0.0702;0.1098).

We can conclude that the true population proportion at 95% of confidence is between (0.0702;0.1098)

Part b

Since the confidence interval NOT contains the value 0.06 we  have anough evidence to reject the claim at 5% of significance.

6 0
1 year ago
I need to write a decimal where the value of a digit is 1/10 as much as a digit in another place
KengaRu [80]
1/10 is the same as saying 10 times less

Refer to the diagram below
The digit as the first decimal place is worth 1/10
The digit as the second decimal place is worth 1/100 which is 1/10 worth the digit as the first decimal place

Example of two decimal numbers:

2.56 and 2.68

The digit 6 in 2.56 is 6/100
The digit 6 in 2.68 is 6/10

The digit 6 in 2.56 is 1/10 as much as the digit 6 in 2.68

6 0
2 years ago
It is known that driving can be difficult in regions where winter conditions involve snow-covered roads. For cars equipped with
noname [10]

Answer:

The null and alternative hypothesis for this test are

H_0: \mu\ge 215\\\\H_1: \mu< 215

Step-by-step explanation:

If we perform a hypothesis test, we can reject or not reject the null hypothesis.

To conclude that the tires have a decreased stopping distance (μ<215), we should state the null hypothesis H_0: \mu\ge 215 and then go on with the analysis to reject it (or not).

If the null hypothesis is rejected, the claim of the manufacturer is rigth.

The alternative hypothesis would be H_1: \mu, that would turn rigth if the null hypothesis is rejected.

5 0
1 year ago
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