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2 years ago

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Forty students are in the science club. Of those, 45% are girls. This percent increases to 56% after new girls join the club. Ho

w many new girls join?

1 answer:

Gekata [30.6K]2 years ago

6 0

Around 22-23 create a function and input these to find the exact

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Compare A and B if 70% of A is equal to $0.7a and 35% of B is equal to $0.35a

MrRa [10]

Answer:

A=B

Step-by-step explanation:

Equation 1: 70% of A = 0.7a

Equation 2: 35% of B = 0.35a

Equation 3 = (Equation 2) • 2

Equation 3: 70% of B = 0.7a

Equation 3 = Equation 1

A = B

3 0

2 years ago

Read 2 more answers

nadia was offered a job for selling ads cor a magazine. She must agree to one of the following paymen options. CHOICE A:$110 for

Fittoniya [83]

Let us say that:

x = is the number of ads that Nadia sold every week

P = payment or amount that she receives every week

So the equations we can formulate for choice A and B are:

choice A: P = 110 x

choice B: P = 150 + 85 x

The amount that she receives for A must be greater than she receives for choice B, so:

110 x > 150 + 85 x (inequality equation)

Calculate for x:

110 x – 85 x > 150

25 x > 150

x > 6

Therefore Nadia must sell more than 6 ads every week so that Choice A would be the better choice.

6 0

2 years ago

Holly bought 23 tickets to the baseball game. She got a group rate that gave her $4 off of the regular ticket price for each tic

sveticcg [70]

Answer:

The regular price of the ticket was $12.

Step-by-step explanation:

Let us call $P$ the regular price of the tickets, and if she had bought tickets at this price, the total cost would have been

$23P$ .

But Holly got $4 off the regular ticket price, that means one ticket cost her

$P-4$

and if she bought 23 tickets it cost her

$23(P-4)$

and we are told this equals $184; therefore we have

$23(P-4)=184$

now we solve this equation the following way:

$23(P-4)=184$

$23P-4(23)=184$

$23P-92=184$

$23P=276$

$\boxed{ P=12}$

Thus, the regular price was $12.

5 0

2 years ago

Read 2 more answers

A campus deli serves 300 customers over its busy lunch period from 11:30 a.m. to 1:30 p.m. A quick count of the number of custom

Irina-Kira [14]

Complete question is;

A campus deli serves 300 customers over its busy lunch period from 11:30 am to 1:30 pm. A quick count of the number of customers waiting in line and being served by the sandwich makers shows that an average of 10 customers are in process at any point in time. What is the average amount of time that a customer spends in process?

Answer:

4 minutes

Step-by-step explanation:

For this question, we will apply Little's law which is is a theorem that determines the average number of items in a stationary queuing system, based on the average waiting time of an item within a system and the average number of items arriving at the system per unit of time.

The formula for the law is:

Inventory = flow rate × flow time.

We are given;

Inventory = 300 customers

flow time is from 11: 30am to 1:30pm which is 2 hours = 120 minutes

Flow rate = 300/120 = 2.5 persons/minute

Now, Making flow rate the subject of the formula earlier given, we have;

flow rate = inventory/ flow time

Flow time is the time each person spends in the process

Thus, plugging in the relevant values, we get ;

We are told that an average of 10 customers are in process at any point in time.

Thus;

Average flow time = average inventory/flow rate = 10/2.5 = 4 minutes

3 0

2 years ago

World wind energy generating1 capacity, W , was 371 gigawatts by the end of 2014 and has been increasing at a continuous rate of

Sunny_sXe [5.5K]

Answer:

a) $W(t) = 371(1.168)^{t}$

b) Wind capacity will pass 600 gigawatts during the year 2018

Step-by-step explanation:

The world wind energy generating capacity can be modeled by the following function

$W(t) = W(0)(1+r)^{t}$

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.

371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.

This means that

$W(0) = 371, r = 0.168$

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts

$W(t) = W(0)(1+r)^{t}$

$W(t) = 371(1+0.168)^{t}$

$W(t) = 371(1.168)^{t}$

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

$W(t) = 371(1.168)^{t}$

$600 = 371(1.168)^{t}$

$(1.168)^{t} = \frac{600}{371}$

$(1.168)^{t} = 1.61725$

We have that:

$\log{a^{t}} = t\log{a}$

So we apply log to both sides of the equality

$\log{(1.168)^{t}} = \log{1.61725}$

$t\log{1.168} = 0.2088$

$0.0674t = 0.2088$

$t = \frac{0.2088}{0.0674}$

$t = 3.1$

It will happen 3.1 years after the end of 2014, so during the year of 2018.

7 0

2 years ago