Answer:
2.35 miles
Step-by-step explanation:
Please find the attachment for visual understanding.
We are told that the library is 1.75 miles directly north from the school and the park is 0.6 miles directly south of the school.
To find distance between library and park we will add distance of library from school to the distance of park from school.
Therefore, library is 2.35 miles away from park.
Answer: No
Step-by-step explanation:
$12-$4.50= $7.50
$7.50*15= $112.50
The Total cost is $135 She will only be making $112.50 in profits.
Answer:
279,936 ways
Step-by-step explanation:
Every day the student has to chose a sandwich from the pile of 6 sandwiches. So this means the student has to make a choice from the 6 sandwiches for the 7 days. Since the order matters, this is a problem of permutations.
Daily the student has the option to chose from 6 sandwiches. So this means, for 7 days, he has to make a choice out of 6 options. Or in other words we can say, the student has to make selection from 6 objects 7 times.
So, the total number of ways to chose the sandwiches will be 6 x 6 x 6 x 6 x 6 x 6 x 6 = 
Alternate Method:
Since the repetition can occur in this case, i.e. a sandwich chosen on one day can also be chosen on other day, the following formula of permutations ca be used:
Number of ways = 
where n is the total number of choices available which is 6 in this case and r is the number of times the selection is to be made which 7 in this case. So,
The number of ways to chose a sandwich will be =
ways
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
Just did it...its the first one...second one....fifth one and sixth one...that..is if your on edegenuity..