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Luda [366]
1 year ago
14

Every day a student randomly chooses a sandwich for lunch from a pile of wrapped sandwiches. If there are six kinds of sandwiche

s, how many different ways are there for the student to choose sandwiches for the seven days of a week if the order in which the sandwiches are chosen matters?
Mathematics
1 answer:
balu736 [363]1 year ago
5 0

Answer:

279,936 ways

Step-by-step explanation:

Every day the student has to chose a sandwich from the pile of 6 sandwiches.  So this means the student has to make a choice from the 6 sandwiches for the 7 days. Since the order matters, this is a problem of permutations.

Daily the student has the option to chose from 6 sandwiches. So this means, for 7 days, he has to make a choice out of 6 options. Or in other words we can say, the student has to make selection from 6 objects 7 times.

So, the total number of ways to chose the sandwiches will be 6 x 6 x 6 x 6 x 6 x 6 x 6 = 6^{7}

Alternate Method:

Since the repetition can occur in this case, i.e. a sandwich chosen on one day can also be chosen on other day, the following formula of permutations ca be used:

Number of ways =  n^{r}

where n is the total number of choices available which is 6 in this case and r is the number of times the selection is to be made which 7 in this case. So,

The number of ways to chose a sandwich will be = 6^{7} = 279936 ways

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Mr. mole left his burrow that lies 7 meters below the ground and started digging his way deeper into the ground, descending at a
Dimas [21]

Answer:

f(t)=-\frac{3}{2}t-7

Step-by-step explanation:

We know that:

  • The initial conditions are -7 meters at 0 minutes.
  • Then, after 6 minutes, he was 16 meters below the ground.

According to these two simple facts we can found the linear function that describes this problem. First, the problem says that Mr. Mole is descending at a constant rate, which is the slope of the function. Now, to calculate the slope we need to points, which are (0;-7) and (6;-16), where <em>t-values </em>are minutes, and <em>y-values </em>are meters. You can see, that the first point is the initial condition and the second point is 6 minutes later.

So, we calculate the slope:

m=\frac{y_{2}-y_{1}}{t_{2}-t_{1}} \\m=\frac{-16-(-7)}{6-0}=\frac{-16+7}{6}=\frac{-9}{6}=\frac{-3}{2}

From the slope we can see that Mr. Mole is descending, because it has a negative sign. Also, the point (0;-7) is on the <em>y-axis</em>, because <em>t</em> is null, so -7 is part of the function. Therefore the function that describes this problem is:

f(t)=-\frac{3}{2}t-7

7 0
2 years ago
Read 2 more answers
Sarah’s stands on a ground and sights the top of a steep Clift at a 60 degree angle of elevation she then steps back 50 meters t
SashulF [63]

Answer:

Cliff is 45 m tall.

Step-by-step explanation:

Given:

Height of Sarah = 1.8 m

Angle of elevation = 60°

Angle of elevation 50 m back = 30°

As shown in the figure we have two right angled triangles SPQ and SPR.

Let the height of the cliff be h meters and h= h_1+h_s.

Using trigonometric ratios:

tan (Ф) = opposite/adjacent

In ΔSPQ.                                        In ΔSPR.

⇒ tan(60) = \frac{h_1}{x} ...equation (i)        ⇒ tan (30)=\frac{h_1}{x+50}  ...equation (ii)

Dividing equation (i) and (ii)

⇒ \frac{tan(60)}{tan(30)} = \frac{h_1}{x} \times \frac{x+50}{h_1}

⇒ 3 = \frac{x+50}{x}

⇒ 3x=x+50

⇒ 3x-x=50

⇒ 2x=50

⇒ x=\frac{50}{2}

⇒ x=25 meters

To find h_1 plugging x=25 in equation (i)

⇒ h_1=x\times tan(60)

⇒ h_1=25\times 1.73

⇒ h_1=43.25 meters

The height of the cliff from ground :

⇒ h= h_1+h_s

⇒ h= 43.25+1.8

⇒ h=45.05 meters

The cliff is 45 m tall to the nearest meter.

8 0
2 years ago
I have 4 times as many 10-cent stamps as 3-cent stamps. I have one less 2-cent stamp than 3 cent stamp. If I have b2-cent stamps
gogolik [260]

Answer:

Value of stamp collection = (45b + 43) cents

Step-by-step explanation:

What we have here is as follows;

if there are x 3-cent stamps, then there are 4x 10-cent stamps

So the number of 2-cent stamps is 1 less than 3 cent stamps and that will be x-1 2 cent stamps

Number of 2 cents stamps = b

This means that x-1 = b

Thus, x = b + 1

So the value of the stamp collection is as follows;

x 3 cents stamps = 3(b+ 1) = 3b + 3 cents

4x 10 cents stamps = 10(4(b + 1)) = 10(4b + 4) = 40b + 40

value of the 2 cents stamp = 2b cents

Total value is thus;

2b + 40b + 40 + 3b + 3 = (45b + 43) cents

5 0
2 years ago
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telo118 [61]
A). because B,C, and D didnt really make any sence


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1 year ago
Tim made a down payment of $1,000. He pays $450 for 36 months. What is the total amount he pays for the car?
aniked [119]
B.) $17,200

Tim paid a total of $17,200 for the car.

Downpayment: $1,000
Total Monthly Payment: $450 * 36 mos. = $16,200

Total car payment = Down payment + Total Monthly Payment
TCP = $1,000 + $16,200
TCP = $17,200
7 0
2 years ago
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