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Alenkasestr [34]
2 years ago
11

Find the area of an equilateral triangle with radius 22 cm. Round to the nearest whole number.

Mathematics
1 answer:
daser333 [38]2 years ago
6 0
In this item, we are given with the radius equal to 22 cm.

This measurement of the radius is the hypotenuse of the 30°-60°-90° triangle formed with the half the measurement of the side of the equilateral triangle being opposite to the 60°  and equal to the hypotenuse times (1/2)(√3)

If we let s be the side of the triangle then,
                 s/2 = r(1/2)(√3)
Multiplying the equation by 2,
                 s = r√3
Substituting,
              s = (22 cm)(√3) = 22√3

The area of the equilateral triangle is computed through the equation,
         A = (√3 / 4)(s²)
Substituting,
     <em>    A = (√3 / 4)(22√3)² = 628.7 cm²</em>

Therefore, the answer to this item is the first choice. 
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5 0
2 years ago
After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ
icang [17]

Answer:

a) Upper Control Limit = 0.10

   Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

            computer manufacturer examined samples of calls to determine

            the frequency of wrong advice given to callers. Each sample

            consisted of 100 calls.

SAMPLE             1   2   3   4   5   6   7   8   9  10 11 12 13 14 15 16

Number of errors 5  3   5   7   4   6   8   4   5    9   3   4   5   6   6   7

To find - a. Determine 95 percent limits.

              b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

  = 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

                                     = 0.0544

⇒P = 0.0544

Now,

Q = 1-P

   = 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = \sqrt{\frac{P.Q}{N} }

                             = 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

        = 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

       = 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0
2 years ago
A certain temperature measurement is performed 500 times. The mean value is 0 deg F and the standard deviation is 1 deg F. Assum
egoroff_w [7]

Answer:

477

Step-by-step explanation:

Given that:

Number of trials (n) = 500

Mean (m) = 0

Standard deviation (s) = 1

how many readings fall within +/- 2.000 deg F of the mean value

Mean of 0 and standard deviation of 1

P(-2 ≤ x ≤ 2)

Using the Z probability calculator :

P(x ≤ 2) = 0.97725 ;

P(x ≤ - 2) = 0.02275

Hence :

P(x ≤ 2) - P(x ≤ - 2) = 0.97725 - 0.02275 = 0.9545

Hence, number of readings in 500 trials:

0.9545 * 500 = 477.25

= 477 values

6 0
1 year ago
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