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2 years ago

Let u=(5,-12) and c=-3 what is || cu || ?A.-39 B.21 C.39 D.51 i need help badly

2 answers:

6 0

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$\mathsf{c}\cdot \overrightarrow{\mathsf{u}}=\mathsf{-\,3\cdot (5,\,-12)}$

Therefore,

$\left\|\mathsf{c}\cdot \overrightarrow{\mathsf{u}}\right\|=\mathsf{\left\|-\,3\cdot (5,\,-12)\right\|}\\\\
\left\|\mathsf{c}\cdot \overrightarrow{\mathsf{u}}\right\|=\mathsf{\left|-\,3\right|\cdot \left\|(5,\,-12)\right\|}\\\\
\left\|\mathsf{c}\cdot \overrightarrow{\mathsf{u}}\right\|=\mathsf{3\cdot \sqrt{5^2+(-12)^2}}$

$\left\|\mathsf{c}\cdot \overrightarrow{\mathsf{u}}\right\|=\mathsf{3\cdot \sqrt{25+144}}\\\\
\left\|\mathsf{c}\cdot \overrightarrow{\mathsf{u}}\right\|=\mathsf{3\cdot \sqrt{169}}\\\\
\left\|\mathsf{c}\cdot \overrightarrow{\mathsf{u}}\right\|=\mathsf{3\cdot \sqrt{13^2}}\\\\
\left\|\mathsf{c}\cdot \overrightarrow{\mathsf{u}}\right\|=\mathsf{3\cdot 13}$

$\left\|\mathsf{c}\cdot \overrightarrow{\mathsf{u}}\right\|=\mathsf{39}\quad\longleftarrow\quad\textsf{this is the answer (option C. 39)}$

I hope this helps. =)

Degger [83]2 years ago

4 0

Answer:39 is the awnser

Step-by-step explanation:

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