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Temka [501]
2 years ago
5

Sam bought brushes for $8, a palette for $5, and oil paints for $15. He paid $29.82 in all. What sales-tax rate did Sam pay?

Mathematics
2 answers:
klio [65]2 years ago
7 0
Total purchased w/o tax: $8 +$5 + $15 = $28
He paid (w/tax) $29.82 so 
$ 29.82 - $28 = $1.82 (sale tax)

Now we need to find the sales tax rate:

$1.82 / $28 * 100 = 0.065 *100% = 6.5%

Double check:

$28 *6.5 / 100  = $1.82

$28 + $ 1.82 =  $29.82 total amount he paid..

So the sales tax rate is 6.5%

expeople1 [14]2 years ago
7 0

Answer:

$1.82 or 6.5%

Step-by-step explanation:

Amount paid by Sam for Purchasing brushes =$ 8

Amount paid by Sam for Purchasing palette =$ 5

Amount paid by Sam for Purchasing oil paints =$ 15

Hence, the total amount to be paid by Sam= $8+$5+$15

Total amount to be paid by Sam=$ 28

Total amount paid by Sam= $29.82

Sales- tax paid by Sam= $29.82- 28

Sales- tax paid by Sam= 1.82

Rate of sales-tax=\frac{1.82}{28}× 100

Rate of sales-tax=6.5%

Hence, the correct answer is 6.5%

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Point Z is equidistant from the vertices of ΔTUV.
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option C. Angle BTZ Is-congruent-to Angle BUZ

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Read 2 more answers
A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th
QveST [7]

we know that

the volume of a cone is equal to

V= \frac{1}{3} \pi r^{2}h

in this problem

the radius is equal to

r= \frac{112}{2}= 56ft

1) <u>Find the height of the cone before the storm</u>

Applying the Pythagorean Theorem find the height

h^{2} = l^{2}-r^{2}

l=65 ft

h^{2} = 65^{2}-56^{2}

h^{2} = 1,089

h=33 ft

2) <u>Find the volume before the storm</u>

V= \frac{1}{3}*\pi* 56^{2}*33

V=34,496\pi\ ft^{3}

3) <u>Find the volume after the storm</u>

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

so

r=(56/3) ft

h=(33/3)=11 ft

V= \frac{1}{3}*\pi* (56/3)^{2}*11

V= 1,277.63\pi\ ft^{3}

<u>4) Find how this change affect the volume of the pile</u>

Divide the volume after the storm by the volume before the storm

\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}

therefore

<u>the answer part a) is</u>

The volume of the pile after the storm is \frac{1}{27} times the original volume

<u>Part b)</u>  Estimate the number of lane miles that were covered with salt

5) <u>Find the amount of salt that was used during the storm</u>

=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}

6) <u>Find the pounds of road salt used</u>

104,358.59*80=8,348,687.2\ pounds    

7) <u>Find the number of lane miles that were covered with salt</u>

8,348,687.2/350=23,853.39 \ lane\ miles  

therefore

<u>the answer part b) is</u>

the number of lane miles that were covered with salt is 23,853.39 \ lane\ miles

<u>Part c) </u>How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to 1,277.63\pi\ ft^{3}

1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}

8) <u>Find the pounds of road salt </u>

4,013.79*80=321,103.20\ pounds

9) <u>Find the number of lane miles </u>

321,103.20/350=917.44 \ lane\ miles

therefore

<u>the answer part c) is</u>

the number of lane miles is 917 \ lane\ miles

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