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stepan [7]
1 year ago
6

The annual salaries of all employees at a financial company are normally distributed with a mean= $34,000 and a standard deviati

on= $4,000. What is the z-score of a company employee who makes an annual salary of $28,000?
Mathematics
2 answers:
Goshia [24]1 year ago
7 0
The question ask the z score of the company having a mean of 34000 and standard deviation of 4000 and the answer would be -1.5. I hope you are satisfied with my answer and feel free to ask for more if you have further question and clarifications
Alexandra [31]1 year ago
7 0

The <em>correct answer</em> is:

-1.5.

Explanation:

The formula for a z-score is

z=\frac{X-\mu}{\sigma}, where X is our test value, μ is the mean, and σ is the standard deviation.

Using our information, we have:

z=\frac{28000-34000}{4000}=\frac{-6000}{4000}=-1.5

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In getting the average of all the measurement you give you need first to sum all the measurements and also make sure that you do it properly. Then divide the sum with the number of measurements. By calculating the answer is 10.288
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2 years ago
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John has taken out a loan for college. He started paying off the loan with a first payment of $100. Each month he pays, he wants
sergeinik [125]
<span>Let a_0 = 100, the first payment. Every subsequent payment is the prior payment, times 1.1. In order to represent that, let a_n be the term in question. The term before it is a_n-1. So a_n = 1.1 * a_n-1. This means that a_19 = 1.1*a_18, a_18 = 1.1*a_17, etc. To find the sum of your first 20 payments, this sum is equal to a_0+a_1+a_2+...+a_19. a_1 = 1.1*a_0, so a_2 = 1.1*(1.1*a_0) = (1.1)^2 * a_0, a_3 = 1.1*a_2 = (1.1)^3*a_3, and so on. So the sum can be reduced to S = a_0 * (1+ 1.1 + 1.1^2 + 1.1^3 + ... + 1.1^19) which is approximately $5727.50</span>
8 0
1 year ago
Identify which line from the graph the following right triangles could lie on.
qaws [65]

Answer:

Step-by-step explanation:

Slope of line A = \frac{\text{Rise}}{\text{Run}}

                         = \frac{9}{3}

                         = 3

Slope of line B = \frac{9}{6}

                         = \frac{3}{2}

Slope of line C = \frac{6}{8}

                         = \frac{3}{4}

5). Slope of the hypotenuse of the right triangle = \frac{\text{Rise}}{\text{Run}}

                                                                                = \frac{90}{120}

                                                                                = \frac{3}{4}

Since slopes of line C and the hypotenuse are same, right triangle may lie on line C.

6). Slope of the hypotenuse = \frac{30}{10}

                                              = 3

Therefore, this triangle may lie on the line A.

7). Slope of hypotenuse = \frac{18}{24}

                                        = \frac{3}{4}

Given triangle may lie on the line C.

8). Slope of hypotenuse = \frac{21}{14}

                                        = \frac{3}{2}

Given triangle may lie on the line B.

9). Slope of hypotenuse = \frac{36}{24}

                                        = \frac{3}{2}

Given triangle may lie on the line B.

10). Slope of hypotenuse = \frac{48}{16}

                                          = 3

Given triangle may lie on the line A.

7 0
1 year ago
In order to estimate the average electricity usage per month, a sample of 125 residential customers were selected, and the month
mr_godi [17]

Answer:

[895.05; 940.81]kWh

Step-by-step explanation:

Hello!

Be X: monthly electricity usage by a residential customer

X~N

σ²: 12100KWh²

To estimate the population mean using a 98% CI you have to use the following formula

[X[bar]±Z_{1-\alpha /2} * \frac{Sigma}{\sqrt{n} }]

1-α: 0.98

α0.02

α/2: 0.01

1-α/2:0.99

Z_{1-\alpha /2}= Z_{0.99}= 2.326

n= 125

X[bar]= ∑X/n= 228565/125= 917.93

[917.93±2.326 * \frac{110}{\sqrt{125} }]

[895.05; 940.81]

Using a 98% confidence level you'd expect that the interval [895.05; 940.81]kWh will include the average monthly electricity usage of residential customers.

I hope this helps!

Raw data:

Electric Usage

765

1139

714

687

1027

1109

749

799

911

631

975

717

1232

806

637

894

856

896

1272

1224

621

606

898

723

817

746

933

595

851

1027

770

685

750

1198

975

678

1050

886

826

1176

583

841

1188

692

733

791

584

1163

593

1234

603

1044

1233

1178

598

904

778

693

590

845

893

1028

975

788

1240

1253

854

1185

1164

741

1058

1053

795

1198

1240

1140

959

938

1008

1035

1085

1100

680

1006

977

1042

1252

943

1165

1014

912

791

612

935

864

953

667

1005

1063

1095

1086

810

1032

970

1099

1229

892

1074

579

754

1007

1116

583

763

1231

966

962

1132

738

1033

697

891

840

725

1031

7 0
2 years ago
Which value, when placed in the box, would result in a system of equations with infinitely many solutions? y = 2x – 5 2y – 4x =
ludmilkaskok [199]
I think the answer is a. -10
8 0
2 years ago
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