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2 years ago

What is half of 2.1 cm

Mathematics

2 answers:

balu736 [363]2 years ago

8 0

Answer:

The answer is 1.05 half of 2.1 ÷ by 2

Eddi Din [679]2 years ago

5 0

Answer:

1.05

Step-by-step explanation:

2 in half is 1 and to split .1 you can go deeper

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In studying the insurance preferences of homeowners the following conclusions are made: A homeowner is three times as likely to

Ede4ka [16]

Answer:

0.632

Step-by-step explanation:

Given that a homeowner is three times as likely to purchase additional jewelry coverage as additional electronics coverage

If probability of purchasing additional electronics coverage = p, then prob of purchasing jewelry coverage = 3p

The two events are independent hence joint probability is product of these two.

i.e. P(both) = $p(3p) =3p^2$

This is given as 0.2

$3p^2 =0.2\\p = 0.258$

the probability that a homeowner purchases exactly one coverage.

$=P(AUB)-P(A \bigcap B)$

= Prob he purchases I + prob he purchases II-2(prob he purchases both)

$= 0.258+3(0.258)-2(0.2)\\=0.632$

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2 years ago

Antawn Jamison is shooting free throws. Making or missing free throws doesn't change the probability that

scoray [572]

Answer: 0.73^9

Step-by-step explanation: Khan

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2 years ago

A round wading pool has a diameter of 115\text{ cm}115 cm115, start text, space, c, m, end text and is 25\text{ cm}25 cm25, star

AveGali [126]

Answer: 6

Step-by-step explanation:

8 0

1 year ago

Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying

svp [43]

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)' [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S) [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

3 0

2 years ago

Members of a school club are buying matching shirts. They know at least 25 members will get a shirt. Long-sleeved shirts are $10

charle [14.2K]

Answer:

Maximum number of long sleeved shirt that can be purchase is, 8

and

Minimum number of long sleeved shirt that can be purchased is, 0

Step-by-step explanation:

let y represents the number of short sleeves and x represents the number of long sleeves.

As per the given condition:

Members of a school club are buying matching shirts. They know at least 25 members will get a shirt.

we have;

$x+y\geq 25$ or

$y\geq 25 -x$ ....[1]

Since, long sleeves shirt are $ 10 each and short sleeves shirt are $ 5 each.

then;

Total cost of long sleeves is 10x and

the total cost of short sleeves is 5y

Also; the club can spend no more than $ 165

then;

$10x+5y\leq 165$

$5y\leq 165 -10x$ or

$y\leq 33-2x$ ......[2]

Solving the inequality equation with the graph :

Plot equation [1] and [2]; we get the maximum at point (8 , 17)

so, x= 8.

If we take minimum value of x =0 then y is between 25 and 33.

so, the solution area is between the lines to the left of where the lines intersect.

Therefore, the maximum number of long sleeved shirts can be purchased is 8 and the minimum number of long sleeved shirt can be purchased is 0

6 0

2 years ago

Read 2 more answers