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marta [7]
2 years ago
13

Six times Jason's collection of books and one-third of Nathan's collection add up to 134 books. One-third of Jason's collection

and Nathan's entire collection add up to 31 books.
Mathematics
1 answer:
zimovet [89]2 years ago
7 0

Answer:

j = 21 and n = 14

Step-by-step explanation:

we have the equations:

6j + n/3 = 134

j/3 + n = 31

54j + 3n = 1206

j + 3n = 93

53j = 1113

j = 21

(21)/3 + n = 31

7 + n = 31

n = 14

please mark brainliest :)

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Rachel has a drawing that measures 4 inches in length and 6 inches in width. She wants to enlarge the drawing to fit on a poster
seropon [69]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
Steve stayed after school for extra activities 55% of the 180 school days this year. How many days did Steve stay after school?
musickatia [10]

Answer:

11/20 or 99/180 days

Step-by-step explanation:

55/100 converted to ?/180

180/100=1.8

so you would do the same on the numerator which is 55*1.8=99

99/180= 33/60=11/20

7 0
2 years ago
Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)
UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations:

C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600

Therefore, the probability is

P=\frac{12117600}{53524680}\\\\P=0.226

b) We calculate the probability that are at least 2 red balls.

We calculate the probability  withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations: for 1 red balls

C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848

Therefore, the probability is

P_1=\frac{16138848}{53524680}\\\\P_1=0.3

We calculate the number of favorable combinations: for none red balls

C_7^{34}=5379616

Therefore, the probability is

P_0=\frac{5379616}{53524680}\\\\P_0=0.1

Therefore, the  the probability that are at least 2 red balls is

P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

C_7^{46}=\frac{46!}{7!(46-7)!}=53524680

We calculate the number of favorable combinations:

C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056

Therefore, the probability is

P=\frac{44056}{53524680}\\\\P=0.0008

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\

Let Y, event that exactly 3 blue balls selected.

P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\

We have

P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12

Therefore, we get

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74

8 0
2 years ago
Consider circle O, in which arc XY measures 16π cm. The length of a radius of the circle is 32 cm.
natali 33 [55]

Answer:

Circumference: 64π

Ratio:      1 : 4

Measure of ∠xoy:  π/2    

Step-by-step explanation:

We are given an arc length of 16π.  Since it's in terms of pi, we use the formula

S = rФ    where r is the radius, and Ф is the measure of the angle in radians (in terms of pi)

We are given S = 16π and r = 32, plug those in and find Ф

16π = 32Ф

  16π/32 = Ф

       π/2 = Ф

This is the measure of the central angle.  

The angle is π/2 radians.  There are 2π radians in the circumference, so the circumference is 4 times the arc length created by the central angle.  (There are 4 halves in 2)  so the ratio of the arc length tothe circumference is 1 : 4

The formula for circumference is C = 2πr, where r is the radius, so we hace

C = 2π(32) = 64π

8 0
2 years ago
Read 2 more answers
Sam has $1,000 to be distributed among two groups equally. Later the first part is divided among five children and second part i
katrin2010 [14]

Let x be the money distributed to the first group and y be the money distributed to the second group.

Then, x + y = 1000

Let c be the money distributed to one child in the first group and b be the money distributed to one brother in the second group.

Then, x = 5c and y = 2b

Hence 5c + 2b = 1000.

4 0
2 years ago
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