Ask question

Ask question

All categories

2 years ago

15

Write an expression to show the average daily change in temperature of the city 2.34 degrees Celsius -2/7 degrees Celsius -0.45

degrees Celsius 3/8 degrees Celsius

1 answer:

baherus [9]2 years ago

8 0

2.34+(-2/7)+(-.45)+3/8= Answer than divide by 4 and that will be your average

You might be interested in

Two standardized tests, a and b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×

Romashka [77]

Answer:

(a) The mean score of test A is 1210.

(b) The mean score of test A is 1210.

(c) The standard deviation of test A is 80.

(d) The value of Q₃ for test A is 1170.

(e) The value of median for test A is 1090.

(f) The value of IQR for test A is 290.

Step-by-step explanation:

The relation between two standardized tests <em>A</em> and <em>B</em> is:

$50A=40B+50$

The equation above approximates the relationship between scores on the two tests.

The summary statistics for test B are as follows:

Lowest Score = 21

Mean score = 29

Standard deviation = 2

Q₃ = 28

Median = 26

IQR = 6

(a)

Compute the lowest score on test A as follows:

$A=40B+50\\=(40\times21)+50\\=890$

Thus, the lowest score on test A is 890.

(b)

Compute the mean score of test A as follows:

<h2> $A=40B+50\\=(40\times29)+50\\=1210$ </h2>

Thus, the mean score of test A is 1210.

(c)

Compute the mean score standard deviation of test A as follows:

<h2> $A=40B+50\\=(40\times2)\\=80$ </h2>

Thus, the standard deviation of test A is 80.

(d)

Compute the value of Q₃ for test A as follows:

$A=40B+50\\=(40\times28)+50\\=1170$

Thus, the value of Q₃ for test A is 1170.

(e)

Compute the value of median for test A as follows:

$A=40B+50\\=(40\times26)+50\\=1090$

Thus, the value of median for test A is 1090.

(f)

Compute the value of IQR for test A as follows:

$A=40B+50\\=(40\times6)+50\\=290$

Thus, the value of IQR for test A is 290.

6 0

2 years ago

In the derivation of the quadratic formula by completing the square, the equation (x+b over 2a)^2=-4ac+b^2 over 4a^2 is created

vredina [299]

Answer:

The result of applying the square root property of equality to this equation is $x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$ .

Step-by-step explanation:

Consider the provided equation.

$\left(x+\dfrac{b}{2a}\right)^2=\dfrac{-4ac+b^2}{4a^2}$

As the above equation is formed by perfect square trinomial so simply applying the square root property as shown:

$\sqrt{(x+\dfrac{b}{2a})^2}=\pm \dfrac{\sqrt{-4ac+b^2}}{\sqrt{4a^2}}\\x+\dfrac{b}{2a}=\pm \dfrac{\sqrt{b^2-4ac}}{2a}$

Isolate the variable x.

$x=-\dfrac{b}{2a}\pm \dfrac{\sqrt{b^2-4ac}}{2a}\\x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Hence, the result of applying the square root property of equality to this equation is $x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$ .

4 0

2 years ago

Read 2 more answers

to estimate the number of bison in the area, researchers put marks on 160 bison later on a flight over the area the researchers

Dvinal [7]

Its either -126 or 160

5 0

2 years ago

1.62 divided by 0.27

Snezhnost [94]

Answer:

The answer is 6

8 0

2 years ago

Read 2 more answers

Which formula can be used to describe the sequence?

Maru [420]

Answer:

B

Step-by-step explanation:

I think your answer will be B! Good luck :)

5 0

2 years ago

Read 2 more answers