Your boss hands you the monthly data that show the number of orders coming into and out of the warehouse. The data are in the ta
ble below. Explain to your boss, in complete sentences, the solution to this system and what the solution represents. Hint: Month is the x value and No. of orders is the y value...there are 2 tables squished together into 1 table. Month No. of orders in No. of orders out January (1) 3 1 February (2) 4 3 March (3) 6 5 April (4) 7 7
1 answer:
The number of orders in is equal to the number of orders out in month 4 (April). It appears the solution represents the time at which warehouse shipments caught up with order quantities.
_____
For this table to make any sense, we have to assume that the year started with 3 orders in January, and that one order was shipped in January. Then the number of orders was 1 or 2 each month after that, and the number of orders shipped per month was 2 each month after that. That is, the tables represent year-to-date totals of orders in and out.
<em>Alternate Interpretation</em>
If the numbers here are actual orders in and out in each of the listed months, it appears the warehouse is getting better at shipping orders. That is, they are increasing the shipment rate by 2 orders a month each month. They will eventually ship enough to cover the total number of orders in (total of 20 by April), but total shipments through April only amount to 16 orders.
You might be interested in
1) set up a problem
you know you want to get an avg of 94 but how do you do avg in the first place. you add up the numbers then divde by the total number of numbers used lol
so
92.5 is the avg number for the last 3 tests
"x" is the 4th test score which we want to find out
"2" is the total number of numbers being added together
so now lets get x to one side
92.5+ x=94*2 (multiply 2 to both sides)
92.5+x=188
x=188-92.5 (subtract 92.5 from both sides)
x= 95.5 this is the score she need to make to avg 94%
2) you can draw a tree diagram. for example Flower1 branches off into 3 diff greens and then each of those greens branch off into 2 for with or with babies breath.
or you can simple multiply 4*3*2. you can do this because all choices are included with no restriction
your total number of options is 24
you know you want to get an avg of 94 but how do you do avg in the first place. you add up the numbers then divde by the total number of numbers used lol
so
92.5 is the avg number for the last 3 tests
"x" is the 4th test score which we want to find out
"2" is the total number of numbers being added together
so now lets get x to one side
92.5+ x=94*2 (multiply 2 to both sides)
92.5+x=188
x=188-92.5 (subtract 92.5 from both sides)
x= 95.5 this is the score she need to make to avg 94%
2) you can draw a tree diagram. for example Flower1 branches off into 3 diff greens and then each of those greens branch off into 2 for with or with babies breath.
or you can simple multiply 4*3*2. you can do this because all choices are included with no restriction
your total number of options is 24
Inequation 1:
to plot the pairs (x, y) for which the inequation holds, draw the line
then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.
we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.
inequation 2:
draw the lines
i) use points (0, -3), (3, -1)
ii)
use points ( 0, 4), (3, 2)
let's use the point P(3, 3) to see what region of the lines need to be coloured:
;
, not true so we color the region not containing this point
not true, so we color the region not containing the point (3, 3)
The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.
to plot the pairs (x, y) for which the inequation holds, draw the line
then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.
we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.
inequation 2:
draw the lines
i)
ii)
let's use the point P(3, 3) to see what region of the lines need to be coloured:
The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.