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scZoUnD [109]
2 years ago
12

jalil and Victoria are each asked to solve the equation ax – c = bx + d for x. Jalil says it is not possible to isolate x becaus

e each x has a different unknown coefficient. Victoria believes there is a solution, and shows Jalil her work:
Mathematics
2 answers:
Pie2 years ago
8 0

Answer:

x = \frac{d+c}{a - b}

Step-by-step explanation:

Equation: ax – c = bx + d

Jalil says it is not possible to isolate x because  x has a different unknown coefficient.

Victoria t. Victoria believes there is a solution

Solving the equation:

ax-c = bx + d

ax - bx= d+c

(a - b)x = d+c

x = \frac{d+c}{a - b}

So, this shows x can be isolated .

Victoria was right .

It was not possible to isolate x if the coefficients of x would be same .

But in the given equation the coefficients of x are not same .

So, Victoria is right.

vladimir1956 [14]2 years ago
4 0

Answer:

Rewrite the expression on the left using the distributive property.

Step-by-step explanation:

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A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un
Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

H_{0}:p1=p2

H_{a}:p1≠p2

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }  where

  • p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
  • p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
  • p is the pool proportion of p1 and p2 (\frac{15+12}{100+100}=0.135)
  • n1 is the sample size of the students from West University (100)
  • n2 is the sample size ofthe students from East University (100)

Then we have z=\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } } ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0
2 years ago
Kaitlyn gave 1/2 of her candy bar to arianna. arianna gave 1/3 of the candy she got from kaitlyn to cameron. what fraction of a
sukhopar [10]
Let the total candy bar be represented by x.

Amount of chocolate Kaitlyn gave to Arianna = \frac{1}{2}x

Amount of chocolate Arianna gave Cameron 

= \frac{1}{3} rd <span>of the candy she got from Kaitlyn to Cameron

= </span>\frac{1}{3} × \frac{1}{2}x

= \frac{1}{3}* \frac{1}{2} x  =  \frac{1}{6} x

Hence, Cameron got \frac{1}{6} th of the original chocolate.
5 0
2 years ago
the ratio of chicken to pigs to horses in a farm is 10:2:3.if there is 120 chickens in the farm then the number of the horses in
Veseljchak [2.6K]

Answer:

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Eddi Din [679]

Answer:

Step-by-step explanation:

Hello!

You have the math and writing SAT scores of twelve students.

There are two variables of interest X₁: Math SAT score of a student. and X₂: Writing the SAT score of a student.

These two variables aren't independent since both of them represent data corresponding to the same student, meaning, that the math and writing scores belong to the same students and not to two separate groups of students.

This is an example of paired samples, to make the statistical test you have to establish a third variable, this variable will be the difference between the other two:

Xd= X₁-X₂

Xd: "Difference between the Math and Writing SAT scores of a student.

This variable has a normal distribution Xd~N(μd;σd²)

a. Using a .05 level of significance and test for a difference between the population mean for the math scores and the population mean for the writing scores? Enter negative values as negative numbers. Round your answer to two decimal places.

The parameter of interest is μd is the population mean of the difference between the math and writing SAT scores of the students.

The hypotheses are:

H₀: μd=0

H₁: μd≠0

α: 0.05

The test statistic is a t-student for dependent samples and it's rejection region is two-tailed.

t= \frac{Xd[bar]-Mud}{Sd/\sqrt{n} } = \frac{25-0}{37.05/\sqrt{12} } = 2.33

What is the p-value? Round your answer to four decimal places.

The p-value for this test is: 0.0394

The p-value is less than the level of significance, the decision is to reject the null hypothesis.

b. What is the point estimate of the difference between the mean scores for the two tests?

The sample mean for the variable "difference" is X[bar]d

You can calculate the point estimate of the sample mean of the variable Xd using two ways.

1) You calculate all the differences between the pairs of scores, add them and divide them by the sample size

X[bar]d= ∑di/n

∑di= 300

n=12

X[bar]d= 300/12= 25

2) You can calculate the sample mean for each variable and then calculate the difference between the two sample means

X[bar]₁= ∑X₁/n

∑X₁= 6168

X[bar]₁= 6168/12= 514

X[bar]₂= ∑X₂/n

∑X₂= 5868

X[bar]₂= 5868/12= 489

X[bar]d= X[bar]₁-X[bar]₂ = 514 - 489= 25

What are the estimates of the population mean scores for the two tests?

Math test X[bar]₁= 514

Writing test X[bar]₂= 489

Which test reports the higher mean score?

The Math test reports a higher mean score.

I hope it helps!

3 0
2 years ago
Jonathan borrowed $475 at a simple annual interest rate of 2%. How many years will it take him to repay the loan if he wants to
vovikov84 [41]
Firstly you would times 475 by the percentage, which you can convert to a decimal my multiplying the percentage by 100.

475 * 0.02 = 9.50

Then divide the interest by the amount of interest per year:
38 / 9.5 = 4.

The answer would be 4 years.

Hope this helps.
3 0
2 years ago
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