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makvit [3.9K]
2 years ago
7

A store manager is looking at past jewelry sales to determine what sizes of rings to keep in stock. The list shows the ring size

s purchased by the last ten jewelry customers. 9, 7, 6.5, 7.5, 7, 8, 5, 6, 7.5, 8 What is the variance of the data? Round to the nearest hundredths.
0.40
0.72
1.15
2.14
Mathematics
2 answers:
Rom4ik [11]2 years ago
4 0
Mean: ( 9 + 7 + 6.5 + 7.5 + 7 + 8 + 5 + 6 + 7.5 + 8 ) : 10 = 7.15
Variance:
(Sigma)² = ( 1.85² + 0.15² + 0.65² + 0.35² + 0.15² + 0.85² + 2.15² + 1.15² + 0.35² + 0.85² ) : 10 ≈ 1.15
Answer: C ) 1.15
erastovalidia [21]2 years ago
4 0
We have that

set of data [9, 7, 6.5, 7.5, 7, 8, 5, 6, 7.5, 8]

 step 1

Find the mean

[9+ 7+ 6.5+ 7.5+ 7+ 8+ 5+ 6+ 7.5+ 8]/10 \\ =71.5/10 \\= 7.15

 step 2

 for each number: subtract the Mean and square the result

(9-7.15) ^{2} =3.4225  \\ (9-7.15) ^{2} =3.4225  \\ (7-7.15)^{2} = 0.0225  \\ (6.5-7.15)^{2} = 0.4225  \\  (7.5-7.15)^{2} = 0.1225  \\ (7-7.15)^{2} = 0.0225 \\  (8-7.15)^{2} = 0.7225 \\ (5-7.15)^{2} = 4.6225  \\  (6-7.15)^{2} = 1.3225  \\ (7.5-7.15)^{2} = 0.1225  \\  (8-7.15)^{2} = 0.7225

Sum=11.525

 step 3

 work out the mean of those squared differences

11.525/10 \\ =1.15

this value is called the "Variance"


the answer is the option

1.15

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