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1 year ago

Which equations have a leading coefficient of 3 and a constant term of –2? Check all that apply.

Mathematics

2 answers:

kvv77 [185]1 year ago

7 0

the answer is a, c, and e

lidiya [134]1 year ago

4 0

Answer:

Answer choices a,c,e, are correct

Step-by-step explanation:

You might be interested in

Write down a pair of integers whose

MrRissso [65]

<span>The pair of integers that I chose are:

(a) sum is –3
5 + (-8) = -3

(b) difference is –5
2 - 7 = -5

(c) difference is 2
14 -12 = 2

(d) sum is 0
2 - 2 = 0</span>

6 0

1 year ago

Find the gradient of the line segment between the points (2,3) and (-3,8).

fiasKO [112]

Answer:

$m = -1$

Step-by-step explanation:

Given

Points (2,3) and (-3,8)

Required

Determine the gradient

Gradient (m) is calculated by dividing the change in y values by the change in x values.

i.e.

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where:

$(x_1,y_1) = (2,3)$

$(x_2,y_2) = (-3,8)$

$m = \frac{y_2 - y_1}{x_2 - x_1}$ becomes

$m = \frac{8 - 3}{-3 -2}$

$m = \frac{5}{-5}$

$m = -1$

<em>Hence, the gradient is -1</em>

7 0

1 year ago

Theresa has hired Chuck and Diana to paint a fence. Diana can paint 150 fence posts in the same time it takes Chuck to paint 130

Alenkasestr [34]

Answer: Chuck can paint 65 posts per hour.

Step-by-step explanation:

The data we have here is:

Diana can paint 150 fence posts in a time T

Chuck can pint 130 fence posts in a time T.

In one hour, Diana can paint 10 more fence posts than Chuck.

If D is the hourly rate of Daian, and C is the hourly rate for Chuck, we have:

D = 150/T

C = 130/T

D = C + 10

we can replace the last equation in the first one and geT:

C + 10 =150/T

C = 130/T

Now we can replace the bottom equation in the above one:

130/T + 10 = 150/T

10 = 150/T - 130/T = 20/T

T*10 = 20

T = 20/10 = 2

So T is 2 hours, then whe have:

D = 150post/2hours = 75 posts per hour.

C = 130 posts/2hours = 65 posts per hour.

4 0

1 year ago

(b) we often read that iq scores for large populations are centered at 100. what percent of these 78 students have scores above

ss7ja [257]

As IQ scores for extensive populaces are focused at 100, the mean = 100.
There ought to be around half scores above or underneath the mean score since mean and middle is about a similar when the populace is substantial.
P(x > 100) = P( z> (100 - 100)/sd ) = P(z > 0)= 0.5
The number of the student who has scored over 100 = 0.5 x 78 = 39 Therefore the answer is 39 students.

4 0

1 year ago

I need help with this quick

ziro4ka [17]

The best answer for this question is A.

Best of luck.

8 0

1 year ago