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ella [17]
2 years ago
13

A tire dealer sells 2 tires for as much as he paid for 3 tires. He paid $240 for a dozen tires. What is the total profit on 12 t

ires?
Mathematics
1 answer:
Mariana [72]2 years ago
5 0

 he paid 240/12 = 20 per tire

 so he pays 20 *3 = 60 for three tires

he sells 2 for 60.  60-40 = 20 profit per 2 tired

20 *6 = $120 profit for 12 tires

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The expression shown can be used to calculate the amount of money in dollars a grocery store customer should receive in change w
Readme [11.4K]

Answer:

The change received by the customer is $7.

Step-by-step explanation:

First, write the given expression for the change when paying with $50.

50 - ( 14 + 12 + 2 ( 5 ) + 2 ( 2 ) + 3 )

Evaluate the parentheses:

50-(26+10+4+3)

Now add the numbers inside the parentheses.

50-43

Subtract the numbers.

7

Hence, the change received by the customer is $7.

4 0
2 years ago
Lee is sewing vests using 16 green buttons and 24 blue buttons. all the vests are identical, and all have both green and blue bu
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Emily invests $5,000 in an
Gemiola [76]

Answer:

50 years

Step-by-step explanation:

use the simple interest formula :

PRT/100

P is the principle (5000)

R is the rate of interest (4)

T is the time taken (x- unknown)

the amount at the end is double the amount invested  = 5000*2 = 10000

(5000*4 * x )/100 = 10000

20000x/100=10000

20000x = 100*10000

20000x = 1 000 000

x= 1 000 000/ 20 000

x = 50

it will take<u> 50 years </u>

7 0
2 years ago
Read 2 more answers
The functions f(x) and g(x) are described using the following equation and table: f(x) = −2(1.07)x x g(x) −4 −10 −2 −7 0 −4 2 1
Natali [406]

Answer:

The y-intercept of f(x) is equal to 2 times the y-intercept of g(x).

Step-by-step explanation:

7 0
2 years ago
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(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
2 years ago
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