Proof: We know that angle CBA is congruent to angle FBA and
that angle CAB is congruent to angle FAB because the corresponding angles have the
same measure in degrees (as evidenced in the given equation). We see that angle
BCA is congruent to angle BFA by the reflexive property of congruence (More
accurately Third Angle Theorem). Therefore, we can conclude that triangle BCA
is congruent to triangle BFA because a pair of corresponding angles and the included side are equal, since the two triangles share a line segment (AB).
Draw the picture and label the
width = w
The length of the monitor is six times the quantity of five less than half its width:
length = 6(w/2-5)
length = 3w-30
Area = (length)*(width)
384=(3w-30)*(w)
384=3w^2-30w
Answer:
the dimensions of the monitor in terms of its width is:
384=3w^2-30w
Answer:
10x=10y so x and y are the same or x=y
Step-by-step explanation:
Answer:
80 cm²
Step-by-step explanation:
Trapezoid LPKB has area ...
A = (1/2)(b1 +b2)h = (1/2)(4 +20)(20) = 240 . . . . cm²
Triangle BPN has area ...
A = (1/2)bh = (1/2)(20)(20) = 200 . . . . cm²
Triangle BKN has a height that is 4/5 the height of triangle BPN, so will have 4/5 the area:
ΔBKN = (4/5)(200 cm²) = 160 cm²
The area of quadrilateral LPKB is that of trapezoid LPNB less the area of triangle BKN, so is ...
240 cm² - 160 cm² = 80 cm²
