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Snowcat [4.5K]
1 year ago
12

A wave is traveling at 36 m/s. If its wavelength is 12 m, how many times does a wavelength move across a set point every second?

Mathematics
2 answers:
Lynna [10]1 year ago
8 0
Basically, what is asked here is the frequency in per second. This could be calculated by dimensional analysis, such that the remaining unit is 1/s.

36 m/s\ / \ 12 m = 3\ s^{-1}

Thus, the answer is three times. Letter B.

I hope I was able to give a good explanation. Thank you.
Sunny_sXe [5.5K]1 year ago
6 0

Answer:

The answer is B. 3 times

                           

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In the following alphanumeric series, what letter comes next? V Q M J H
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2 years ago
A really bad carton of eggs contains spoiled eggs. An unsuspecting chef picks eggs at random for his ""Mega-Omelet Surprise."" F
Dima020 [189]

Answer:

(a) The probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b) The probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c) The probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

Step-by-step explanation:

The complete question is:

A really bad carton of 18 eggs contains 8 spoiled eggs. An unsuspecting chef picks 5 eggs at random for his “Mega-Omelet Surprise.” Find the probability that the number of unspoiled eggs among the 5 selected is

(a) exactly 5

(b) 2 or fewer

(c) more than 1.

Let <em>X</em> = number of unspoiled eggs in the bad carton of eggs.

Of the 18 eggs in the bad carton of eggs, 8 were spoiled eggs.

The probability of selecting an unspoiled egg is:

P(X)=p=\frac{10}{18}=0.556

A randomly selected egg is unspoiled or not is independent of the others.

It is provided that a chef picks 5 eggs at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.556.

The success is defined as the selection of an unspoiled egg.

The probability mass function of <em>X</em> is given by:

P(X=x)={5\choose x}(0.556)^{x}(1-0.556)^{5-x};\ x=0,1,2,3...

(a)

Compute the probability that of the 5 eggs selected exactly 5 are unspoiled as follows:

P(X=5)={5\choose 5}(0.556)^{5}(1-0.556)^{5-5}\\=1\times 0.05313\times 1\\=0.0531

Thus, the probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b)

Compute the probability that of the 5 eggs selected 2 or less are unspoiled as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

              =\sum\imits^{2}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=0.0173+0.1080+0.2706\\=0.3959

Thus, the probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c)

Compute the probability that of the 5 eggs selected more than 1 are unspoiled as follows:

P (X > 1) = 1 - P (X ≤ 1)

              = 1 - P (X = 0) - P (X = 1)

              =1-\sum\limits^{1}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=1-0.0173-0.1080\\=0.8747

Thus, the probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

6 0
1 year ago
A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height of the rocket in
kiruha [24]

Answer:

282ft

Step-by-step explanation:

83×3=249

249+33=282

4 0
1 year ago
Hello, I was wondering if someone would be able to help me with this problem I'm on. Thanks :)
koban [17]

<span><span>Price after trade discount = $14,000 - (40% trade discount)

Price after trade discount = $14,000 - ($14,000 * 0.4)

Price after trade discount = $14,000 - ($5,600)

Price after trade discount = $8,400 </span>Price after trade discount = $8,400

2/10 EOM price = $8,400 - (2% discount)

2/10 EOM price = $8,400 - ($8,400 * 0.02)

2/10 EOM price = $8,400 - ($168)

2/10 EOM price = $8,232

So Intel will pay $8,232 on August 5.
Hope this helps.
</span>
4 0
1 year ago
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