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Snowcat [4.5K]
1 year ago
12

A wave is traveling at 36 m/s. If its wavelength is 12 m, how many times does a wavelength move across a set point every second?

Mathematics
2 answers:
Lynna [10]1 year ago
8 0
Basically, what is asked here is the frequency in per second. This could be calculated by dimensional analysis, such that the remaining unit is 1/s.

36 m/s\ / \ 12 m = 3\ s^{-1}

Thus, the answer is three times. Letter B.

I hope I was able to give a good explanation. Thank you.
Sunny_sXe [5.5K]1 year ago
6 0

Answer:

The answer is B. 3 times

                           

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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
2 years ago
A local factory uses a manufacturing process in which 70% of the final products meet quality standards and 30% are found to be d
frosja888 [35]
<span>Answer:
   a manufacturing process has a 70% yield, meaning that 70% of the porducts are acceptable and 30% are defective. If three of the products are randomly selected, find the probability that all of them are acceptable. ---
   Ans: 0.7^3 = 0.3430.</span>
8 0
2 years ago
In a study in Scotland (as reported by Devlin 2009), researchers left a total of 320 wallets around Edinburgh, as though the wal
Ann [662]

Answer:

a) The observed proportion of wallets that were returned

  p = 0.45625

b) <em> 95% of confidence intervals for Population proportion</em>

<em>  0.40168  , 0.51082)</em>

<em>c) The lower bound of the 95% confidence interval = 0.40168</em>

<em>d) The upper bound of the 95% confidence interval = 0.51082</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

a)

Given data the  researchers left a total of 320 wallets around Edinburgh, as though the wallets were lost. Each contained contact information including an address. Of the wallets, 146 were returned by the people who found them

Given sample size 'n' = 320

  Given data          'x ' = 146

<em>Sample proportion </em>

              p = \frac{x}{n}

             p = \frac{x}{n} = \frac{146}{320} = 0.45625

<u><em>Step(ii)</em></u>:-

b)<em> </em><u><em>95% of confidence intervals for Population proportion</em></u>

Level of significance = 95% or 0.05%

Z_{\frac{\alpha }{2} } = Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96

<em>95% of confidence intervals for Population proportion are determined by</em>

<em></em>(p - Z_{0.025} \frac{\sqrt{p(1-p)} }{\sqrt{n} } , p + Z_{0.025} \frac{\sqrt{p(1-p)} }{\sqrt{n} })<em></em>

<em></em>(0.45625 - 1.96\frac{\sqrt{0.45625(1-0.45625)} }{\sqrt{320} } , 0.45625 + 1.96\frac{\sqrt{0.45625(1-0.45625)} }{\sqrt{320} })<em></em>

<em>(0.45625 - 0.05457 , 0.45625 + 0.05457)</em>

<em>(   0.40168  , 0.51082) </em>

<em>c) The lower bound of the 95% confidence interval = 0.40168</em>

<em>d) The upper bound of the 95% confidence interval = 0.51082</em>

7 0
2 years ago
Marilyn has 10 caramels, 12 mints, and 14 bars of dark chocolate in a bag. She picks three items from the bag without replacemen
Gemiola [76]
10+12+14 = 36

12/36 x 11/35 x 14/34 = 11/255

There's your answer.
3 0
2 years ago
Read 2 more answers
2. At a local restaurant, 55% of people order an appetizer to start while 25%
nekit [7.7K]

Answer:

Probability of people order a salad or an appetizer P(A∪B) = 62%

Step-by-step explanation:

Given:

Probability of appetizer P(A) = 55%

Probability of salad P(B) = 25%

Probability of choose both P(A∩B) = 18%

Find:

Probability of people order a salad or an appetizer P(A∪B)

Computation:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 55% + 25% - 18%

P(A∪B) = 62%

Probability of people order a salad or an appetizer P(A∪B) = 62%

5 0
2 years ago
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