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2 years ago

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A jury pool consists of 27 people. How many different ways can 11 people be chosen to serve on a jury and one additional person

be chosen to serve as the jury foreman?

1 answer:

hichkok12 [17]2 years ago

4 0

Answer:

208,606,320

Step-by-step explanation:

A jury pool consists of 27 people. 11 people be chosen to serve on a jury and one additional person be chosen to serve as the jury foreman

Total of 27 people. 11 people can be selected from 27 people in 27C11 ways

$27C11= \frac{27!}{11!(27-11)!} =13037895$

one additional person be chosen to serve as the jury foreman

after selecting 11 people , remaining is 27 - 11= 16 people

Now 1 is selected from 16 in 16 ways

Number of different ways = $13037895 \cdot 16=208606320$

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The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

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Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

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(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

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$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

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Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

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$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

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This is n when M = 0.05. So

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$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

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