<span>-Both box plots show the same interquartile range.
>Interquartile range (IQR) is computed by Q3-Q1.
For Mr. Ishimoto's class, Q3 is 35 and Q1 is 31. 35-31 = 4.
For Ms. Castillo's class, Q3 is 34 and Q1 is 30. 34-30 = 4.
</span><span>-Mr. Ishimoto had the class with the greatest number of students.
>Mr. Ishimoto had 40 students, represented by the last data point of the whiskers.
</span><span>-The smallest class size was 24 students.
>Which was Ms. Castillo's class.</span>
Ur answer is (0,-3)
because ur line is a solid line, this means any number on that line is a solution....along with any points that are in the blue area. when u plot ur answer choices, if it falls in the white area, it is not a solution
Answer:
The equation are:
1) h + s = 20
2) 4h = 1s
Step-by-step explanation:
Number of hats Elliott made = h
Number of scarfs Elliott made = s
total number of items Elliott made = 20
h + s = 20 ..[1]
1 hat uses 0.2 kilograms of yarn
1 hat = 0.2 kg of yarn
Then h hats will use = 0.2h kg of yarn
1 scarf uses 0.1 kilograms of yarn
1 scarf= 0.1 kg of yarn
Then s scarfs will use = 0.1s kg of yarn
She wants to twice as much as yarn for scarves for hats:
2 × (0.2h kg of yarn) = 0.1s kg of yarn
0.4h = 0.1s
4h = 1s...[2]
The equation are:
1) h + s = 20
2) 4h = 1s
You have to answer all of the equations first
-4.8 • 3.2 = -15.36 (negative times a positive is negative)
2 1/4 + (-1 2/5) first find a common denominator, which would be 20
9/4= 45/20
-7/5 = -28/20
since adding a negative is the same as subtracting a positive, you would subtract 45 and 28 which is 17.
17/20 = 1 3/20 (the answer)
turn the fraction into a decimal by dividing the top number by the bottom number, so 17/20 = 0.85
4.92 divided by -3 equals -1.64 (the answer)
-2 3/5 - (-1 2/5)
make them into improper fractions which is -13/5 and -7/5
it stays negative, so the answer is -6/5 or -1.2
so the answer is
-4.8 • 3.2 < 4.2 divided by -3 < -2 3/5 - (-1 2/5) < 2 1/4 + (-1 2/5)
Answer:
The one with arrows are the answers
->Line segment E B is bisected by Line segment D F .
->A is the midpoint of Line segment F C .
Line segment F C bisects Line segment D B.
->Line segment E B is a segment bisector.
->FA = One-halfFC.
Line segment D A is congruent to Line segment A B .
Step-by-step explanation:
I did it on edge and got it right
