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Lynna [10]
2 years ago
9

Bella has joined a new gym in town. The cost of membership is $25 per month. The after-hours policy at the gym allows her to wor

k out late at night for an extra fee of $4 per visit. If Bella's first monthly bill totaled $53, which equation can be used to determine how many times Bella worked out after hours?
Mathematics
1 answer:
hjlf2 years ago
4 0

The total monthly bill of the gym = $53

The cost of membership of a month = $25

Let 'n' be extra the number of hours Bella worked on.

The cost for working on extra hours = $4

So, we have to determine the equation, Bella worked out after hours.

We will determine the equation by:

(Monthly cost of membership) + ( cost for extra hours \times number of hours extra worked on )  = Total monthly bill received

So, we get

\$25+(4 \times n) = \$53

$25+4n = $53 is the required equation.

Therefore, $25+4n = $53  equation can be used to determine how many times Bella worked out after hours.

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Answer: $1411.50

Step-by-step explanation:

Since the sale price is $35 each and there are 30 units, the cost will be:

= $35 × 30

= $1050

We then add the sales tax on the product which is 8%. This will be:

= $1050 + (8% × $1050)

= $1050 + (0.08 × $1050)

= $1050 + $84

= $1134

We then add Shipping price which is $15. This will be:

= $1134 + $15

= $1149

We then add the 25% rush charge on the sales price. This will be:

= $1050 × 25%

= $1050 × 0.25

= $262.50

To get total cost, this will be:

= $1149 + $262.50

= $1411.50

5 0
2 years ago
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Answer:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

Step-by-step explanation:

Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"

We have the following formula in order to find the sum of cubes:

\lim_{n\to\infty} \sum_{n=1}^{\infty} i^3

We can express this formula like this:

\lim_{n\to\infty} \sum_{n=1}^{\infty}i^3 =\lim_{n\to\infty} [\frac{n(n+1)}{2}]^2

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\lim_{n\to\infty} \frac{n^2(n+1)^2}{n^4}

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We can do some algebra and we got:

\lim_{n\to\infty} (1+\frac{1}{n})^2

We can solve the square and we got:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2})

And when we apply the limit we got that:

\lim_{n\to\infty} (1+ \frac{2}{n} +\frac{1}{n^2}) =1

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2 years ago
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Answer:

D) x - 0.34x

Step-by-step explanation:

25% + 9% = 34% = 0.34

Will pay 34% in taxes, means he subtracts from is annual income.

x - 0.34x

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What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.?
swat32
The answer would be 1017.88 in³. Use the volume for cones ( 1/3 times pi times radius times height) so 1/3*3.14*9*12 in which would be 1017.88 in³ hope it helps!
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