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Lynna [10]
2 years ago
9

Bella has joined a new gym in town. The cost of membership is $25 per month. The after-hours policy at the gym allows her to wor

k out late at night for an extra fee of $4 per visit. If Bella's first monthly bill totaled $53, which equation can be used to determine how many times Bella worked out after hours?
Mathematics
1 answer:
hjlf2 years ago
4 0

The total monthly bill of the gym = $53

The cost of membership of a month = $25

Let 'n' be extra the number of hours Bella worked on.

The cost for working on extra hours = $4

So, we have to determine the equation, Bella worked out after hours.

We will determine the equation by:

(Monthly cost of membership) + ( cost for extra hours \times number of hours extra worked on )  = Total monthly bill received

So, we get

\$25+(4 \times n) = \$53

$25+4n = $53 is the required equation.

Therefore, $25+4n = $53  equation can be used to determine how many times Bella worked out after hours.

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Sanjay and his paving crew laid 40 yards of new pavement. Jack and his crew just took over, and they can lay 15 yards of new pav
Mila [183]

Answer:

40 yds \: + 8hrs\times  \frac{15yds}{hr }  =  \\ 40yds+ 120yds \: = 160yds

5 0
1 year ago
Louden County Wildlife Conservancy counts butterflies each year. Data over the last three years regarding four types of butterfl
MrRa [10]

Incomple question. However, here's the remaining part of the question:

14

2009

Meadow Fritillary= 5

Variegated Fritillary= 7

Zebra Swallowtail= 33

Eastern-Tailed Blue= 242

Louden County Butterfly Count

2010

Meadow Fritillary 34

Variegated Fritillary 95

Zebra Swallowtail 21

Eastern-Tailed Blue 168

2011

Meadow Fritillary

Variegated Fritillary

Zebra Swallowtail

Eastern-Tailed Blue

10

170

<u>Options</u>:

A) All butterfly populations are steadily decreasing.

B)All butterfly populations were larger than usual in 2010.

C)The Eastern-Tailed Blue butterfly is more common than the others.

D)The Meadow Fritillary is equally common as the Variegated Fritillary

Answer:

<u>C</u>

Step-by-step explanation:

Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.

Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.

5 0
2 years ago
Jeff and Kayla are finding the product of 178 times 56.They both are using the distributive property to find partial products.Lo
UNO [17]

Answer:

9968

Step-by-step explanation:

178×56=178×(50+6)

=178×50+178×6

=8900+(170+8)×6

=8900+170×6+8×6

=8900+1020+48

=9968

6 0
2 years ago
Maggie is considering two investments. Investment A Investment B Principal $10,000 $8,000 Interest rate 3% 2.8% Time in years 5
lana [24]
To solve this we are going to use the simple interest formula: A=P(a+rt)
where
A is the final amount.
P is the initial investment. 
r is the interest rate in decimal form.
t is the time in years. 

Investment A. We know that the initial investment is $10,000, so P=10000. We also know that the number of years is 5, so t=5. To convert the interest rate to decimal form, we are going to divide the rate by 100%
r= \frac{3}{100} =0.03
Lets replace those values in our formula to find A:
A=P(a+rt)
A=10000(1+0.03*5)
A=11500

Investment B. P=8000, t=15, and r= \frac{2.8}{100} =0.028.
A=P(a+rt)
A=8000(1+0.028*15)
A=11360

We can conclude that investment A will be worth than investment B at the end of the investment period.
3 0
2 years ago
Read 2 more answers
The assistant manager of a surf shop estimates that 65% of customers will make a purchase. Part A: How many customers should a s
Ivan

Answer:

A) 2

B) 0.239

Step-by-step explanation:

Part A) Expected value of a binomial distribution is the number of trials times the probability of success.

X = np

Given X = 1 and p = 0.65:

1 = 0.65n

n = 1.54

Rounding up, a salesperson should expect 2 customers until he finds a customer that makes a purchase.

Part B) Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

Given n = 3, r = 1, p = 0.65, q = 0.35.

P = ₃C₁ 0.65¹ 0.35³⁻¹

P ≈ 0.239

Or, using binompdf function in a calculator:

binompdf(n, p, r)

= binompdf(3, 0.65, 1)

≈ 0.239

3 0
2 years ago
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