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zavuch27 [327]
1 year ago
11

The Stolen Book. Betty tells Susan that Bob stole her business law book from her car. The next day Susan confronts Bob and slaps

him for stealing her book. Bob has Susan arrested for slapping him. Susan sues Bob for damages in the amount of the book and for maliciously having her arrested. Claiming that she lied, Bob sues Betty for defamation. The prosecution by the government against Susan for slapping Bob involves which of the following?
A. Public law
B. Private law
C. Comprehensive law
D. Administrative law
E. Both public and private law
Mathematics
1 answer:
leva [86]1 year ago
3 0
I believe it is a hope this helps
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Consider the following random sample from a normal population: 14, 10, 13, 16, 12, 18, 15, and 11. What is the 95% confidence in
seraphim [82]

Answer:

13.625-2.365\frac{2.669}{\sqrt{8}}=11.393  

13.625+2.365\frac{2.669}{\sqrt{8}}=15.857  

So on this case the 95% confidence interval would be given by (11.393;15.857)  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Data: 14, 10, 13, 16, 12, 18, 15, 11

We can calculate the sample mean and deviation with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=13.625 represent the sample mean  

\mu population mean (variable of interest)  

s=2.669 represent the sample standard deviation  

n=8 represent the sample size  

Calculate the confidence interval

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=8-1=7  

Since the confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,7)".And we see that t_{\alpha/2}=2.365

Now we have everything in order to replace into formula (1):  

13.625-2.365\frac{2.669}{\sqrt{8}}=11.393  

13.625+2.365\frac{2.669}{\sqrt{8}}=15.857  

So on this case the 95% confidence interval would be given by (11.393;15.857)  

3 0
1 year ago
The height of a baseball thrown from the catcher to first base is modeled by the function h(t)=-0.08t^2+0.72t+6, where h is the
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The answer would be c
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A craft stick fits exactly on the diagonal across the bottom of the rectangular craft box shown in the diagram below.
enyata [817]
Well first you got to add up of the sides
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2 years ago
An entry level web developer's annual pay is $55,640 based on 52 weeks per year. Due to the economy, his company is having to cu
katen-ka-za [31]

Answer:

Reduction = \$3300

Step-by-step explanation:

Given

Pay\ for\ 52\ weeks = \$55,640

Required

Determine the reduction when paid is reduced to 49 weeks

First, we need to determine the weekly pay

Weekly\ Pay = \frac{\$55,640}{52}

Weekly\ Pay = \$1070

Next, is to determine the pay for 49 weeks;

Pay = Weekly\ Pay * 49

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Subtract the 49 week pay from 52 weeks pay to get the payment reduction;

Reduction = \$55640 - \$52340

Reduction = \$3300

5 0
1 year ago
The number of acres in a region cleared for farming follows the formula a = f (t) = 2t2 where t is the number of months since th
Anit [1.1K]

we are given

a=f(t)=2t^2

we can use average rate of change formula from t=a to t=b

A=\frac{f(b)-f(a)}{b-a}

Here, we are given from t=1 to t=4

so, we will get formula as

A=\frac{f(4)-f(1)}{4-1}

now, we can plug values

A=\frac{2(4)^2-2(1)^2}{4-1}

now, we can simplify it

A=10

the average rate of change in the number of acres cleared for farming between t = 1 and t = 4  is 10 acres/ month.............Answer

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2 years ago
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