All categories

1 year ago

Which statements about the box plot are correct? Check all that apply.

Mathematics

2 answers:

love history [14]1 year ago

6 0

Answer:

The correct options are 1 and 3.

Step-by-step explanation:

From the given box plot it is clear that

Q₁ is 25% of a data.

Median is 50% of a data.

Q₃ is 75% of a data.

34 is minimum value of the data and 46 is median it means 50% of the data values lies between 34 and 46. Therefore option 1 is correct.

42 is first quartile and and 70 is third quartile. it means 50% of the data values lies between 42 and 70. Therefore option 2 is incorrect.

The difference between Minimum value and first quartile, Maximum value and third quartile is less than 1.5×(IQR), therefore it is unlikely to have any outliers in the data.

Hence option 3 is correct.

The interquartile range of the data is

The interquartile range is 28. Therefore option 4 is incorrect.

Range of the data is

The range is 42. Therefore option 5 is incorrect.

Step-by-step explanation:

Rudiy271 year ago

3 0

Answer:

The correct options are 1 and 3.

Step-by-step explanation:

From the given box plot it is clear that

$\text{Minimum values}=34$

$Q_1=42$

Q₁ is 25% of a data.

$Median=46$

Median is 50% of a data.

$Q_3=70$

Q₃ is 75% of a data.

$\text{Maximum values}=76$

34 is minimum value of the data and 46 is median it means 50% of the data values lies between 34 and 46. Therefore option 1 is correct.

42 is first quartile and and 70 is third quartile. it means 50% of the data values lies between 42 and 70. Therefore option 2 is incorrect.

The difference between Minimum value and first quartile, Maximum value and third quartile is less than 1.5×(IQR), therefore it is unlikely to have any outliers in the data.

Hence option 3 is correct.

The interquartile range of the data is

$IQR=Q_3-Q_1$

$IQR=70-42=28$

The interquartile range is 28. Therefore option 4 is incorrect.

Range of the data is

$Range=Maximum-Minimum$

$Range=76-34=42$

The range is 42. Therefore option 5 is incorrect.

You might be interested in

Solve the system of linear equations using multiplication.

Anna71 [15]

Answer:

$(8,-1)$

Step-by-step explanation:

The given system is:

$3x+3y=21$

$6x+12y=36$

Since I prefer to use smaller numbers I'm going to divide both sides of the first equation by 3 and both sides of the equation equation by 6.

This gives me the system:

$x+y=7$

$x+2y=6$

We could solve the first equation for $x$ and replace the second $x$ with that.

Let's do that.

$x+y=7$

Subtract $y$ on both sides:

$x=7-y$

So we are replacing the second $x$ in the second equation with $(7-y)$ which gives us:

$(7-y)+2y=6$

$7-y+2y=6$

$7+y=6$

$y=6-7$

$y=-1$

Now recall the first equation we arranged so that $x$ was the subject. I'm referring to $x=7-y$ .

We can now find $x$ given that $y=-1$ using the equation $x=7-y$ .

Let's do that.

$x=7-y$ with $y=-1$ :

$x=7-(-1)$

$x=7+1$

$x=8$

So the solution is (8,-1).

We can check this point by plugging it into both equations.

If both equations render true for that point, then we have verify the solution.

Let's try it.

$3x+3y=21$ with $(x,y)=(8,-1)$ :

$3(8)+3(-1)=21$

$24+(-3)=21$

$21=21$ is a true equation so the "solution" looks promising still.

$6x+12y=36$ with $(x,y)=(8,-1)$ :

$6(8)+12(-1)=36$

$48+(-12)=36$

$36=36$ is also true so the solution has been verified since both equations render true for that point.

5 0

2 years ago

Read 2 more answers

$36 for 4 baseball hats; $56 for 7 baseball hats are they equivalent

Arlecino [84]

36/4 = 9 per hat
56/7 = 8 per hat

no, they are not equivalent

5 0

2 years ago

The Bay Area Online Institute (BAOI) has set a guideline of 60 hours for the time it should take to complete an independent stud

yarga [219]

Answer:

At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 60 \ hr$

The sample size is $n = 16$

The sample mean is $\= x = 68 \ hr$

The standard deviation is $\sigma = 20 \ hr$

The null hypothesis is $H_o : \mu = 60$

The alternative $H_a : \mu > 60$

Here we would assume the level of significance of this test to be

$\alpha = 5\% = 0.05$

Next we will obtain the critical value of the level of significance from the normal distribution table, the value is $Z_{0.05} = 1.645$

Generally the test statistics is mathematically represented as

$t = \frac{ \= x - \mu}{ \frac{ \sigma }{\sqrt{n} } }$

substituting values

$t = \frac{ 68 - 60 }{ \frac{ 20 }{\sqrt{16} } }$

$t = 1.6$

Looking at the value of t and $Z_{\alpha }$ we see that $t< Z_{\alpha }$ hence we fail to reject the null hypothesis

This means that there no sufficient evidence to conclude that it takes more than 60 hours to complete the course

At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

6 0

1 year ago

Consider the function f(x)=(x+4)(x+2). Dilate f(x) by X to create a new function of a higher degree

Marat540 [252]

Answer:

Consider the function f (x) = (x +4) (x + 2).

Step-by-step explanation:

4 0

1 year ago

The graph represents the piecewise function: f(x) = What is the domain and range of the function? Domain: Range:

White raven [17]

Answer:

domain: All real numbers

Range: all real numbers greater than or equal to 0

Step-by-step explanation:

Edge 2020

4 0

1 year ago

Read 2 more answers