Question

If the quantity 4 times x times y cubed plus 8 times x squared times y to the fifth power all over 2 times x times y squared is completely simplified to 2xayb + 4xcyd, where a, b, c, and d represent integer exponents, what is the value of a? _______

Answer 1

$\dfrac{4xy^3 + 8x^2y^5 }{2xy^2}$

$= \dfrac{4xy^3(1+2xy^2)}{2xy}$

$= 2y^2(1 + 2xy^2)$

$= 2y^2 + 4xy^4$

Answer: a = 1, b 2, c = 1, d = 4