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Bond [772]
2 years ago
9

Is the sum of the areas of two smaller squares equal to the area of a large square if the sides lengths of the squares are 8 fee

t, 5 feet, and 3 feet?
Mathematics
1 answer:
77julia77 [94]2 years ago
5 0
No.
The sum of the areas of the two smaller squares is 5^2 + 3^2 = 34
The area of the larger square is 8^2=64
34 does not = 64
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Explain how to find the greatest number of identical arrangements that can be made with 54 roses and 42 tulips with no flowers l
Basile [38]
Work out the Greatest Common Factor for both numbers

54                                         421×54                                   1×422×27                                  2×213×18                                   3×146×9                                    6×7

The common factors are: 1, 2, 3 and 6
The greatest common factor is 6
There are 6 identical arrangements that can be made
 
There will be 9 roses and 7 tulips in each arrangement

3 0
2 years ago
Read 2 more answers
Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim
Xelga [282]

Answer: P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = \frac{2.\pi}{B}

C is the phase shift or horizontal shift: \frac{C}{B}

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

<u>Amplitude</u>:

a = \frac{largest - smallest}{2}

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = \frac{6.9-4.4}{2}

a = 1.25

<u>b</u>

A time period for Pluto is T=66 years:

66 = \frac{2.\pi}{b}

b = \frac{\pi}{33}

<u>Vertical</u> <u>Shift</u>

It can be calculated as:

d = \frac{largest+smallest}{2}

d = \frac{6.9+4.4}{2}

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin(\frac{\pi}{3}.t) + 5.65

8 0
2 years ago
Consider this system of inequalities. x + y ≤ –3 y &lt; StartFraction x Over 2 EndFraction Which graph shows the solution for th
miss Akunina [59]

Answer:

the answer is c

Step-by-step explanation:

i just did it

6 0
2 years ago
The perpendicular bisector of the line segment connecting the points $(-3,8)$ and $(-5,4)$ has an equation of the form $y = mx +
docker41 [41]

Answer:

m = -1/2 and b = 6.5

Step-by-step explanation:

To find the slope of the original line segment, we have to do the change in y/the change in x:

(4-8)/(-5--3) = -4/-2 = 2

2 is the slope of the original line segment, but since this is the perpendicular bisector, we have to take the negative reciprocal of 2 so m = -1/2

To find b we substitute the values of x, y, and m into the equation. Let's use the x value of -3 and the y value of 8:

y = mx + b

8 = -1/2(-3) + b

8 = 3/2 + b

6.5 = b

5 0
2 years ago
A patient is instructed to take three 50-mcg tablets of pergolide mesylate (Permax) daily. How many milligrams of the drug would
Black_prince [1.1K]

Answer:

The patient would receive 1.05mg of the drug weekly.

Step-by-step explanation:

First step: How many mcg of the drug would the patient receive daily?

The problem states that he takes three doses of 50-mcg a day. So

1 dose - 50mcg

3 doses - x mcg

x = 50*3

x = 150 mcg.

He takes 150mcg of the drug a day.

Second step: How many mcg of the drug would the patient receive weekly?

A week has 7 days. He takes 150mcg of the drug a day. So:

1 day - 150mcg

7 days - x mcg

x = 150*7

x = 1050mcg

He takes 1050mcg of the drug a week.

Final step: Conversion of 1050 mcg to mg

Each mg has 1000 mcg. How many mg are there in 1050 mcg? So

1mg - 1000 mcg

xmg - 1050mcg

1000x = 1050

x = \frac{1050}{1000}

x = 1.05mg

The patient would receive 1.05mg of the drug weekly.

6 0
2 years ago
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