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charle [14.2K]
2 years ago
15

Elia rode her bicycle from her house to the beach at a constant speed of 18 kilometers per hour, and then rode from the beach to

the park at a constant speed of 15 kilometers per hour the total duration of the rides was 1 hour and the distances she rode in each direction are equal. Let b be the number of hours it took Elia to ride from her house to the beach, and p the number of hours it took her to ride from the beach to the park
Mathematics
2 answers:
jonny [76]2 years ago
7 0

Answer:

b+p=1 and 18b=15p

Step-by-step explanation:

ASHA 777 [7]2 years ago
5 0

Answer:

Elia was riding \dfrac{5}{11} of an hour from the house to the beach, \dfrac{6}{11} of an hour from the beach to the house and rode

8\dfrac{2}{11} kilometers from the house to the beach and

8\dfrac{2}{11} kilometers from the beach to the house.

Step-by-step explanation:

1. Let b be the number of hours it took Elia to ride from her house to the beach, and p the number of hours it took her to ride from the beach to the park. The total duration of the rides was 1 hour, so

b + p = 1

2. Elia rode her bicycle from her house to the beach at a constant speed of 18 kilometers per hour, she was riding for b hour, then she rode 18b kilometers from her house to the beach.

Elia rode from the beach to the park at a constant speed of 15 kilometers per hour, she was riding for p hours, then she rode 15p kilometers from the beach to the house.

The distances she rode in each direction are equal, so

18b = 15p

3. Solve the system of two equations:

\left\{\begin{array}{l}b+p=1\\ \\18b=15p\end{array}\right.

From the first equation

b=1-p

Substitute it into the second equation

18(1-p)=15p\\ \\18-18p=15p\\ \\18=18p+15p\\ \\33p=18\\ \\p=\dfrac{18}{33}=\dfrac{6}{11}\\ \\b=1-\dfrac{6}{11}=\dfrac{5}{11}

Elia was riding \dfrac{5}{11} of an hour from the house to the beach, \dfrac{6}{11} of an hour from the beach to the house and rode

18\cdot \dfrac{5}{11}=\dfrac{90}{11}=8\dfrac{2}{11} kilometers to the beach and

15\cdot \dfrac{6}{11}=\dfrac{90}{11}=8\dfrac{2}{11} kilometers fro mthe beach to the house.

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Now we need to find the probability that the project will completed in 38 weeks given that its expected completion time is 40 weeks.

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2 years ago
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How to factorise 5h^2-12hg​
bonufazy [111]

Answer:

h(5h-12g)

Step-by-step explanation:

5h^2-12hg

When we factor expressions, we look for factors within the terms that are alike, or in other words, we look for common factors. Here, 5h^2 and 12hg only have one common factor: h. Therefore, to factorize this expression, divide both terms by h.

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Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap
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Answer:

The value of the parameter is λ is 0.03553357

Step-by-step explanation:

Consider the provided function.

f(x) = 0.5\lambda e^{-\lambda |x|} for −∞ < x < ∞.

It is given that standard deviation is given as 39.8 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

\lambda=\frac{1}{\beta} and μ = 0.

Standard deviation = √2β

S.D=\sqrt{2} \beta\\\beta=\frac{39.8}{\sqrt{2}}\\\beta=28.1424

Now substitute the value of β in \lambda=\frac{1}{\beta}.

\lambda=\frac{1}{28.1424}=0.03553357

Hence, the value of the parameter is λ is 0.03553357

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2 years ago
In triangle XYZ, XY = 13, YZ=20, and XZ=25. What is the measure of angle Z to the nearest degree?
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Suppose that only 20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe
Lina20 [59]

Answer:

a) 91.33% probability that at most 6 will come to a complete stop

b) 10.91% probability that exactly 6 will come to a complete stop.

c) 19.58% probability that at least 6 will come to a complete stop

d) 4 of the next 20 drivers do you expect to come to a complete stop

Step-by-step explanation:

For each driver, there are only two possible outcomes. Either they will come to a complete stop, or they will not. The probability of a driver coming to a complete stop is independent of other drivers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

This means that p = 0.2

20 drivers

This means that n = 20

a. at most 6 will come to a complete stop?

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.2)^{0}.(0.8)^{20} = 0.0115

P(X = 1) = C_{20,1}.(0.2)^{1}.(0.8)^{19} = 0.0576

P(X = 2) = C_{20,2}.(0.2)^{2}.(0.8)^{18} = 0.1369

P(X = 3) = C_{20,3}.(0.2)^{3}.(0.8)^{17} = 0.2054

P(X = 4) = C_{20,4}.(0.2)^{4}.(0.8)^{16} = 0.2182

P(X = 5) = C_{20,5}.(0.2)^{5}.(0.8)^{15} = 0.1746

P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 + 0.1091 = 0.9133

91.33% probability that at most 6 will come to a complete stop

b. Exactly 6 will come to a complete stop?

P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091

10.91% probability that exactly 6 will come to a complete stop.

c. At least 6 will come to a complete stop?

Either less than 6 will come to a complete stop, or at least 6 will. The sum of the probabilities of these events is decimal 1. So

P(X < 6) + P(X \geq 6) = 1

We want P(X \geq 6). So

P(X \geq 6) = 1 - P(X < 6)

In which

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 = 0.8042

P(X \geq 6) = 1 - P(X < 6) = 1 - 0.8042 = 0.1958

19.58% probability that at least 6 will come to a complete stop

d. How many of the next 20 drivers do you expect to come to a complete stop?

The expected value of the binomial distribution is

E(X) = np = 20*0.2 = 4

4 of the next 20 drivers do you expect to come to a complete stop

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