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blondinia [14]
2 years ago
12

In a café, drinks are priced according to what size they are.

Mathematics
1 answer:
Andrei [34K]2 years ago
8 0
A) Gavin’s drinks altogether cost £9.00
1.50+2.50x3
=1.50+7.50
=£9.00
b) Lian gets back £3.50
1.50+2.00+3.00
=6.50

10.00-6.50=£3.50
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In ΔVWX, x = 5.3 inches, w = 7.3 inches and ∠W=37°. Find all possible values of ∠X, to the nearest 10th of a degree.
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Answer:

que?

Step-by-step explanation:

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1 year ago
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Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was \$43.25$43.25dollar sign, 43,
Elodia [21]

Answer:

29 minutes

Step-by-step explanation:

Given

Total = \$43.25

Entrance\ Fee = \$7

Per\ Minute = \$1.25

Required

Determine the number of minutes (t) that he was on the trampoline.

This can be expressed as:

Total\ Payment = Entrance\ Fee + Amount\ per\ minute * t

Where t represents the number of minutes

Substitute values for Total, Entrance Fee and Amount per minute

43.25 = 7 + 1.25 * t

43.25 = 7 + 1.25t

Solving further to get the value of t, we have:

1.25t = 43.25 - 7

1.25t = 36.25

t = 36.25/1.25

t = 29

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2 years ago
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Mrs. Ibarra wants to create a right triangle for a geometry test. She plans to use 15, 36, and 41 as side lengths. Which stateme
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Answer:

Step-by-step explanation:

The answer is A, C, D, and E. I just took the test.

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Joint and Combined Variations
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Source:
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Coupons driving visits. A store randomly samples 603 shoppers over the course of a year and nds that 142 of them made their visi
s2008m [1.1K]

Answer:

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

7 0
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