You can solve this by making a proportion.
you cross multiply and divide to solve this. your answer is 8.
you cross multiply and divide to solve this. your answer is 8.
What is the measure of Angle D F E?
1 answer:
<u>Given</u>:
Given that the measure of the exterior angle F is 142°
We need to determine the measure of ∠DFE
<u>Measure of ∠DFE:</u>
The ∠DFE and the exterior angle F are linear pairs.
Thus, the linear pair of angles add up to 180°
Hence, we have;
Subtracting both sides of the equation by 142, we get;
Hence, the measure of ∠DFE is 38°
Thus, Option a is the correct answer.
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Answer:
Step-by-step explanation:
step 1
Find PN
we know that
PN is a diameter
PS is a radius
so
step 2
Find the measure of arc MP
step 3
Find the measure of angle MNP
we know that
The inscribed angle measures half that of the arc comprising
substitute the value
step 4
Find the measure of angle MPN
we know that
The inscribed angle measures half that of the arc comprising
substitute the value
step 5
Find the measure of angle NMP
The sum of the internal angles of a triangle must be equal to 180 degrees
therefore
The triangle MNP is a right triangle
step 6
Find the length MN
In the right triangle MNP
substitute the values
Answer:
12,345 tablets may be prepared from 1 kg of aspirin.
Step-by-step explanation:
The problem states that low-strength children’s/adult chewable aspirin tablets contains 81 mg of aspirin per tablet. And asks how many tablets may be prepared from 1 kg of aspirin.
Since the problem measures the weight of a tablet in kg, the first step is the conversion of 81mg to kg.
Each kg has 1,000,000mg. So
1kg - 1,000,000mg
xkg - 81mg.
1,000,000x = 81
x = 0.000081kg
Each tablet generally contains 0.000081kg of aspirin. How many such tablets may be prepared from 1 kg of aspirin?
1 tablet - 0.000081kg
x tablets - 1kg
0.000081x = 1
x = 12,345 tablets
12,345 tablets may be prepared from 1 kg of aspirin.
Answer:
The correct options are;
1) ΔBCD is similar to ΔBSR
2) BR/RD = BS/SC
3) (BR)(SC) = (RD)(BS)
Step-by-step explanation:
1) Given that RS is parallel to DC, we have;
∠BDC = ∠BRS (Angles on the same side of transversal)
Similarly;
∠BCD = ∠BSR (Angles on the same side of transversal)
∠CBD = ∠CBD = (Reflexive property)
Therefore;
ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency
2) Whereby ΔBCD ~ ΔBSR, we therefore have;
BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1
1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1
SC/BS = RD/BR
Inverting both sides
BR/RD = BS/SC
3) From BR/RD = BS/SC the above we have by cross multiplication;
BR/RD = BS/SC gives;
BR × SC = RD × BR → (BR)(SC) = (RD)(BR).
