Answer:
C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
Step-by-step explanation:
The center for Simulation A and Simulation B will be roughly equal.
Overall Sample size of Simulation A = 1500 * 100 = 150000
Overall Sample size of Simulation B = 2000 * 50 = 100000
Since the sample size for Simulation A is greater, the variability of Simulation will be less.
Therefore, The answer is C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
Answer:
5.75x10^11
Step-by-step explanation:
quotient of 2,300 and (0.4x10^-8) is
2,300 ÷ (0.4x10^-8)
2300 = 2.3x10^3
We now have
2.3x10^3 / 0.4x10^-8
= (2.3/0.4) x ( 10^(3 - (-8))
= 5.75 x (10^(3+8))
= 5.75 x (10^11)
= 5.75x10^11
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To answer problems like this you have to use binomial:
P (x > 1) = 1 – p (0
< x < 1) > .7
So:
1 – p (0) – p (1) >
.7
1 – (3/ 4) ^n – (3/ 4)
^n (n – 1 ) (1/ 4) > .7
Therefore n > 5.185,
and the smallest value of n so that we can satisfy the given condition is 6
(rounded up)
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Opposite angles formed by two intersecting lines are equal, so angle 1 is the same as angle 4. That means angle 1 = angle 5 as well.
<span>When a line intersects two parallel lines, the corresponding angles are equal. That is, if r and s are parallel, then the angles formed when l intersects r are the same s the angles formed when l intersects s. Angle 1 = Angle 5, Angle 2 = Angle 6, and so forth. Since we know angle 1 = angle 5, we can conclude that r and s are parallel.</span>
