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2 years ago

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Mike watches a caterpillar climbing on a tree trunk he writes the expression -5/8-(-1/8-1/2) to show the change in feet of the c

aterpillar height on the tree trunk. What is the overall change in the caterpillars height on the tree trunk in feet?

1 answer:

guapka [62]2 years ago

7 0

Answer:

-5 / 8 - -4 / 8 equals the approximate estimate notation of 58.7

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Here is a circle touching a square. The area of the square is 36cm squared. Work out the area of the circle. Give your answer in

Lena [83]

Answer:

see below

Step-by-step explanation:

Because the area of the square is 36 its side is 6 meaning the circle has a diameter of 6. This means that its radius is 3 so its area is 3² * π = 9π.

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Jim lost 4 lbs each week for 10 weeks. Express his total weight change as an integer.

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Answer:

4:10

Step-by-step explanation

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2 years ago

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A ball is kicked upward with an initial velocity of 68 feet per second. The ball's height, h (in feet), from the ground where it

ivann1987 [24]

Acceleration due to gravity is 32.2 ft/s^2

68=32.2t
t=2.11 seconds

h=68t-32.2/2*t^2
h(2.11)=68*2.11-32.2/2*2.11^2
h=71.8 feet

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2 years ago

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in a group of 140 adults, 92 watch tennis, 81 play a sport and 40 do neither. find the probability that an adult chosen at rando

coldgirl [10]

Step-by-step explanation:

27.7%

Step-by-step explanation:

Let's call:

n: the number of adults interviewed

t: number of adults who watch tennis

d: number of adults who practice some sport

x: number of adults who watch tennis and do not practice a sport

The probability that a randomly chosen adult watches tennis and does not play any sports is calculated as follows:

- We calculate the probability that a selected adult will see tennis.

P(t) = 92/140 = 0.657

- We calculate the probability that an adult plays a sport:

P(d) = 81/140 = 0.5786

- We calculate the probability that an adult will see tennis and play some sport (See diagram attached)

P (t ∩ d) = 0.657 (0.5786) = 0.3802

Finally the probability that an adult who sees tennis does not play any sport is:

P(x) = P(t) - P(t ∩ d) = 0.657 - 0.3802

P(x) = 0.277

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2 years ago

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100 random samples were taken from a large population. A particular numerical characteristic of sampled items was measured. The

Marta_Voda [28]

Answer:

The median is $Median = 0.903$

Step-by-step explanation:

From the question we are told that

The sample size is n = 100

The $1^{st} \to 45^{th}$ measurements is $= 0.859 \to 0.900$

Generally since that after 0.900 we have 0.901 , then the

$46^{th} \ measurement \ is \ 0.901$

in the same manner the $47^{th} \ measurement \ is \ 0.902$ ,

Given that 0.902 was observed three times it means that

$47^{th},48^{th},49^{th} \ measurement \ is \ 0.902$ ,

Given that 0.903 was observed two times it means that

$50^{th},51^{th} \ measurement \ is \ 0.903$ ,

Given that 0.903 was observed four times it means that

$52^{nd},53^{rd},54^{th},55^{th} \ measurement \ is \ 0.904$ ,

Given that the highest measurement is 0.958 then then the $56^{th} \to 100^{th} \ measurement \ is \ between \ 0.905 \to 0.958$

Generally the median is is mathematically represented as

$Median = \frac{ [\frac{n^{th}}{2}] + [(\frac{n}{2})^{th} + 1 ]}{2}$

=> $Median = \frac{ [\frac{100^{th}}{2}] + [(\frac{100}{2})^{th} + 1 ]}{2}$

=> $Median = \frac{ [50^{th}] + [51^{th} ]}{2}$

=> $Median = \frac{ 0.903 + 0.903}{2}$

=> $Median = 0.903$

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2 years ago