There are 2 red marbles and 3 blue marbles, with a total of 5 marbles in the bag.
When Jonathan chooses a marble, we are saying that he is choosing the marble randomly.
Let's make a fraction. We want to know the chance of picking one of the 2 red marbles among all 5 marbles.
Divide 2 by 5
2/5
That's already a simplified fraction. If you want to convert this into decimal and into percentage, you would get
2/5
= 0.4
= 40%
Those are all acceptable answers.
Have an awesome day! :)
Given f(n+1) =-2f(n)
here f(n) =f(1) = -1.5
f(n+1) =f(2) = -2 * -1.5 = 3
First, let me do the Mathematical part of that, and then I shall explain the theory behind it.
Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.
Multiply 513 with 6 first.
513
x46
--------------------------
18 (as 6*3 = 18)
60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)
Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.
Check: If we check the multiplication result by using the calculator, we would get the same result (23598).
Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.
27. Replace b with 7, making 6 + 3(7). The 3 and parentheses of 7 hint multiplication, so you multiply to make 21, then add 6 relating back to PEMDAS to teach you the correct order to solve the problem.
