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Yakvenalex [24]

1 year ago

11

Determine the values of c so that the following functions represent joint probability distributions of the random variables X an

d Y : (a) f(x,y)=cxy, forx =1 ,2,3; y =1 ,2,3; (b) f(x,y)=c|x−y|, forx = −2,0,2; y = −2,3.

2 answers:

Xelga [282]1 year ago

8 0

Answer:

A: f(x,y)= 1/36xy;X=1,2,3; y=1,2,3

B: c=1/15

Step-by-step explanation:

Attached is the complete solving.

Anna11 [10]1 year ago

7 0

Answer:

The joint probility density will be c = 1/36

The joint probability distribution will be c = 1/15

Step-by-step explanation:

For step by step explanation see the pucture attached

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bazaltina [42]

Answer:

The total amount paid by Jill = $ (3 d)

Step-by-step explanation:

Here, the cost of 1 book = $ d

Now, the number of books purchased by Jill = 3

So, the total cost of 3 books = 3 x ( Cost of 1 book)

= 3 x ($d) = 3 d

So, if Jill purchased 3 books, the total amount paid by her = $ (3 d)

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What is the common difference between successive terms in the sequence? 0.36, 0.26, 0.16, 0.06, –0.04, –0.14,

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2 years ago

Find the surface area of the regular pyramid shown in the accompanying diagram. If necessary, express your answer in simplest ra

Oksana_A [137]

Answer:

The area of the pyramid is 360 unit²

Step-by-step explanation:

Given

Base Edge, a = 10

Height, h = 12

Required

Determine the surface area

The surface area of a regular pyramid is calculated as thus;

$A = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2}$

Substitute values for a and h

$A = 10^2 + 2 * 10 * \sqrt{\frac{10^2}{4} + 12^2}$

Evaluate all squares

$A = 100 + 2 * 10 * \sqrt{\frac{100}{4} + 144}$

$A = 100 + 2 * 10 * \sqrt{25 + 144}$

$A = 100 + 2 * 10 * \sqrt{169}$

Take positive square root of 169

$A = 100 + 2 * 10 * 13$

$A = 100 + 260$

$A = 360$

<em>Hence, the area of the pyramid is 360 unit²</em>

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1 year ago

An investor with a stock portfolio worth several hundred thousand dollars sued his broker and brokerage firm because he felt tha

marusya05 [52]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

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2 years ago

If h:k = 2:5, x:y=3:4 and 2h+x:k+2y = 1:2, find the ratio h-x: k-y.

fenix001 [56]

Given:

$h:k=2:5,x:y=3:4,2h+x:k+2y=1:2$

To find:

$h-x:k-y$

Solution:

We have, $h:k=2:5$ and $x:y=3:4$ .

Let the values of h and k are 2a and 5a respectively.

Let the values of x and y are 3b and 4b respectively.

We have,

$2h+x:k+2y=1:2$

It can be written as

$\dfrac{2h+x}{k+2y}=\dfrac{1}{2}$

$\dfrac{2(2a)+(3b)}{5a+2(4b)}=\dfrac{1}{2}$

$\dfrac{4a+3b}{5a+8b}=\dfrac{1}{2}$

$2(4a+3b)=1(5a+8b)$

On further simplification, we get

$8a+6b=5a+8b$

$8a-5a=8b-6b$

$3a=2b$

$a=\dfrac{2b}{3}$

Now,

$h-x:k-y=\dfrac{h-x}{k-y}$

$h-x:k-y=\dfrac{2-3b}{5a-4b}$

$h-x:k-y=\dfrac{2\times \dfrac{2b}{3}-3b}{5\times \dfrac{2b}{3}-4b}$

$h-x:k-y=\dfrac{\dfrac{4b}{3}-3b}{\dfrac{10b}{3}-4b}$

On further simplification, we get

$h-x:k-y=\dfrac{\dfrac{4b-9b}{3}}{\dfrac{10b-12b}{3}}$

$h-x:k-y=\dfrac{-5b}{-2b}$

$h-x:k-y=\dfrac{5}{2}$

$h-x:k-y=5:2$

Therefore, the ratio $h-x:k-y$ is $5:2$ .

8 0

1 year ago