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Yakvenalex [24]
1 year ago
11

Determine the values of c so that the following functions represent joint probability distributions of the random variables X an

d Y : (a) f(x,y)=cxy, forx =1 ,2,3; y =1 ,2,3; (b) f(x,y)=c|x−y|, forx = −2,0,2; y = −2,3.

Mathematics
2 answers:
Xelga [282]1 year ago
8 0

Answer:

A: f(x,y)= 1/36xy;X=1,2,3; y=1,2,3

B: c=1/15

Step-by-step explanation:

Attached is the complete solving.

Anna11 [10]1 year ago
7 0

Answer:

The joint probility density will be c = 1/36

The joint probability distribution will be c = 1/15

Step-by-step explanation:

For step by step explanation see the pucture attached

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Maslowich

Answer:

x is the correct answer

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1 year ago
The distribution of annual profit at a chain of stores was approximately normal with mean \mu = \$66{,}000μ=$66,000mu, equals, d
Pepsi [2]

Answer:

The closest to the maximum profit is  x = \$ 83682

Step-by-step explanation:

From the question we are told that

  The  mean is  \mu  =  \$66,000

   The standard deviation is  \sigma  = \$ 21000

   The percentage of profit is  20%

Generally the closest to the maximum annual profit at a store where the executives conducted an audit is mathematically evaluated  as follows

     P(X >  x ) =  0.20

=>  P(X >  x ) = P(\frac{X -x}{\sigma }  >  \frac{x -66000}{21000} ) =  0.20

From the z-table  the z-score for  0.20  is  

    z-score =  0.842

So

     \frac{x -66000}{21000}  = 0.842

=>   x = \$ 83682

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2 years ago
David can proofread15 reports in an hour while Armando can proofread 37reports in an hour. If they have 400 reports to proofread
ycow [4]
Together, it would take them 6 hours
8 0
1 year ago
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Maddy is carrying a 555 liter jug of sports drink that weighs 7.5\text{ kg}7.5 kg7, point, 5, start text, space, k, g, end text.
Lelu [443]

Answer:

w/2 = 7.5/5

3kg

Step-by-step explanation:

Remaining question below:

Which proportion could Maddy use to model this situation?

a. w/2 = 7.5/5

b. w/7.5 = 5/2

Solve the proportion to determine the weight of a 2 liter jug.

_____kg

5 liters jug of sport drink weighs 7.5kg

2 liters jug of sport drink will weigh x kg

Find w

Ratio of weight to volume

7.5kg : 5liters=7.5/5

wkg : 2 liters=w/2

Equates the ratio

7.5 / 5 = w / 2

Cross product

7.5*2=5*w

15=5w

Divide both sides by 5

3=w

w=3kg

Therefore, weight of the 2liters jug of sport drink is 3kg

6 0
1 year ago
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In estimating the mean score on a fitness exam, we use an original sample of size n = 30 and a bootstrap distribution containing
ioda

Answer:

C. 67.5 to 72.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The width of the interval is determined by it's margin of error, which is given by the following formula:

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So, as n increases, the margin of error decreases, and the interval gets smaller.

Using 10,000 bootstrap samples for the distribution:

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So the correct answer is:

C. 67.5 to 72.

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