The smallest number of tiles Quintin will need in order to tile his floor is 20
The given parameters;
- number of different shapes of tiles available = 3
- area of each square shape tiles, A = 2000 cm²
- length of the floor, L = 10 m = 1000 cm
- width of the floor, W = 6 m = 600 cm
To find:
- the smallest number of tiles Quintin will need in order to tile his floor
Among the three different shapes available, total area of one is calculated as;

Area of the floor is calculated as;

The maximum number tiles needed (this will be possible if only one shape type is used)

When all the three different shape types are used we can get the smallest number of tiles needed.
The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

Thus, the smallest number of tiles Quintin will need in order to tile his floor is 20
Learn more here: brainly.com/question/13877427
A product is the answer that you get when you multiply numbers together. So for this problem, you have 2 groups to multiply together. Since I cannot show a square or cubed x, I will put an x2 for x squared and an x3 for x cubed. You have to multiply each number in the first parentheses by each number in the second parentheses. Then combine any like sets.
(8x-3)(x2-4x+8)
8x3-32x2+64x-6x+12x-24
8x3-32x2+70x-24
So the answer is 8x cubed minus 32x squared plus 70x minus 24. Whew! That's a long one. Hope I didn't miss anything.
Answer:
The width of the pathway is:
Step-by-step explanation:
To identify the width of the pathway, you must remember the area formula of a rectangle:
- Area of a rectangle = length * width.
From which the width can be cleared:
- Width of a rectangle = area / length.
We know that the length of the terrain was not modified since the pathway is in the perimeter of the rectangle (16 m) and that the new area is 240 m^2, so we only have to replace the cleared formula:
- Width of a rectangle = 240 m^2 / 16 m = 15 m.
The new width is equal to 15 meters, but since the question is not the total width but the width of the pathway, the width of the previously provided land must be subtracted from the value obtained.
- <u>Pathway width = Total width - Garden width.
</u>
- <u>Pathway width = 15m - 8m = 7 meters.</u>
Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:

The amount of deer that were initally in the reserve corresponds to the value of N when t=0


A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
Answer:
Option (1). 34°
Step-by-step explanation:
From the figure attached, CE and CD are the radii of the circle C.
Central angle CED formed by the intercepted arc DE = 68°
Since measure of an arc = central angle formed by the intercepted arc
Therefore, m∠CED = 68°
Since m∠EFD =
[Central angle of an intercepted arc measure the double of the inscribed angle by the same arc]
Therefore, m∠EFD = 
= 34°
Therefore, Option (1) 34° will be the answer.