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PSYCHO15rus [73]

1 year ago

10

Circle G and X connect at point Y. The length of G Y is 10 centimeters and the length of Y X is 16 centimeters. Point G is the c

enter of the small circle. Point X is the center of the large circle. Points G, Y, and X are all on line segment GX. Marco wants to create a new circle using GX as a radius. What will be the area of Marco's new circle? 10Pi centimeters squared 16Pi centimeters squared 356Pi centimeters squared 676Pi centimeters squared

2 answers:

poizon [28]1 year ago

8 0

Answer:

its b

Step-by-step explanation:

damaskus [11]1 year ago

7 0

Answer:

The area will be $676\pi cm^{2}$

Step-by-step explanation:

I add a graph of the situation.

The first step is to find the length of the radius from the new circle.

The length will be the distance between the point ''G'' and ''X''.

This distance is equal to $10cm+16cm=26cm$

The new radius will be $26cm$

The area of a circle is equal to $\pi .R^{2}$ (I)

Where ''R'' is the radius.

Using the equation (I) :

$Area=\pi .(26cm)^{2}$

$Area=676\pi cm^{2}$

The area of the new circle will be $676\pi cm^{2}$

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The area of the rectangle is 64.8 square centimeters. What is the perimeter of the rectangle? One group of ten tenths and one gr

9966 [12]

Answer:

(a) $Perimeter = 32.2\ cm$

(b) 100

Step-by-step explanation:

Solving (a):

Given

Shape: Rectangle

$Area = 64.8$

Required

Calculate the perimeter.

Area is calculated as:

$Area = L * W$

Where

$L = Length$ and $W = Width$

Substitute 64.8 for Area

$64.8 = L * W$

Make L the subject:

$L = \frac{64.8}{W}$

Perimeter is calculated as:

$P = 2 * (L + W)$

Substitute 64.8/W for L

$P = 2 * (\frac{64.8}{W} + W)$

$P = \frac{129.6}{W} + 2W$

To solve further, we take the derivative of P and set it to 0, afterwards.

$dP = -\frac{129.6}{W^2} + 2$

Set to 0

$0 = -\frac{129.6}{W^2} + 2$

Collect Like Terms

$\frac{129.6}{W^2} = 2$

Cross Multiply:

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Divide through by 2

$W^2 = 64.8$

Take square roots

$W = \sqrt{64.8$

$W = 8.05$

Recall that:

$L = \frac{64.8}{W}$

So:

$L= \frac{64.8}{8.05}\\$

$L= 8.05$

The perimeter is:

$Perimeter = 2 * (8.05 + 8.05)$

$Perimeter = 2 * (16.10)$

$Perimeter = 32.2\ cm$

Solving (b):

Given

((1 Group of 10 tenths) and (1 group of 8 tenths))/(6 groups of 3 tenths)

Required

Solve

$Tenths = \frac{1}{10}$

So, the expression becomes:

((1 Group of $10 * \frac{1}{10}$ ) and (1 group of $8 * \frac{1}{10}$ ))/(6 groups of $3 * \frac{1}{10}$ )

This gives:

((1 Group of $\frac{10}{10}$ ) and (1 group of $\frac{8}{10}$ ))/(6 groups of $\frac{3}{10}$ )

Group means product, so the expression becomes:

$\frac{(1 * \frac{10}{10} \ and\ 1 * \frac{8}{10})}{6 * \frac{3}{10}}$

And, as used here means addition

$\frac{(1 * \frac{10}{10} + 1 * \frac{8}{10})}{6 * \frac{3}{10}}$

Simplify:

$\frac{(1 * 1 + 1 * 0.80)}{6 *0.30}$

$\frac{(1 + 0.80)}{1.80}$

$\frac{1.80}{1.80}$

$= 1.00$

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Answer with explanation:

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D: Consecutive angles of a parallelogram are supplementary.→→→→True

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