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2 years ago

14

The basketball game had 500 people in attendance. If the ratio of hawk fans to cyclone fans is 2:10, how many more cyclone fans

were there

1 answer:

vovangra [49]2 years ago

4 0

There were 5 times the number of hawk fans :)

You might be interested in

1. Three friends pooled their money to purchase a new game system that costs $298. One person

iragen [17]

Answer:

First person: $107

Second person: $98

Third person: $93

Step-by-step explanation:

Let be "f" the amount of money (in dollars) that the first person contributed to the purchase, "s" the amount of money (in dollars) that the second person contributed to the purchase and "t" the amount of money (in dollars) that the third person contributed to the purchase.

With the information given in the exercise, you can set up the following equations:

Equation 1 → $f+s+t=298$

Equation 2 → $s=f-9$

Equation 3 → $t=f-14$

Substitute the Equations 2 and 3 into the Equation 1 and then solve for "f":

$f+(f-9)+(f-14)=298\\\\3f-23=298\\\\f=\frac{321}{3}\\\\f=107$

Finally, substitute the value of "f" into the Equation 2 and then into the Equation 3, in order to find the values of "s" and "t".

Therefore, you get:

$s=107-9\\\\s=98\\\\\\t=107-14\\\\t=93$

5 0

2 years ago

The following chart shows a store?s records of coat sales over two years. 2 circle graphs. A circle graph titled 2006. Top coats

Mkey [24]

Answer:

<u>The correct answer is A. 16.5%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly and to calculate the trend:

2006 2007 Trend

Top Coats 297 223 -24.92%

Parkas 210 210 + 0%

Jackets 213 285 +33.80%

Raincoats 137 259 +89.05

Trench coats 103 127 +23.30%

Total 960 1,104 +15%

2. If the trend shown in these graphs stays constant, what percent of the market will parkas occupy in 2008?

Let's calculate the percent of the market occupied by parkas.

In 2006 = 210/960 = 21.88%

In 2007 = 210/1,104 = 19.02%

In 2008 = 210/1,270 = 16.54% (210 + 0 = 210; 1,104 + 15% = 1,270)

<u>The correct answer is A. 16.5%</u>

7 0

2 years ago

Read 2 more answers

Calculate a23 for the product of the following matrices

s344n2d4d5 [400]

If $A$ is the matrix product

$A=\underbrace{\begin{pmatrix}1&2\\4&3\end{pmatrix}}_{M_1}\underbrace{\begin{pmatrix}6&1&5\\7&3&4\end{pmatrix}}_{M_2}$

and $a_{2,3}$ is the entry of $A$ in the second row and third column, then

$a_{2,3}=\begin{pmatrix}4&3\end{pmatrix}\begin{pmatrix}5\\4\end{pmatrix}=4\times5+3\times4=\boxed{32}$

That is, the 2nd row, 3rd column entry of $A$ is the product of the 2nd row of $M_1$ and the 3rd column of $M_2$ .

6 0

2 years ago

Olive oil is a cooking Ingredient. The density of olive oil is 0.92 grams per cubic centimeter. An olive farmer wants to sell bo

sveticcg [70]

Answer: The volume of container that holds 460 grams of oil is 500 cm³.

Step-by-step explanation:

Density of olive oil is $0.92 grams/(centimetre )^3$

An olive farmer wants to sell bottles that contain 460 grams of oil.

Therefore

Mass of oil = 460 grams

As we know

$\text {Density}= \dfrac{\text{Mass}}{\text{Volume}} \\\\\Rightarrow 0.92= \dfrac{460}{\text{Volume}} \\\\\Rightarrow \text{Volume}= \dfrac{460}{0.92} = 500$

Hence, the volume of container that holds 460 grams of oil is 500 cm³.

7 0

2 years ago

The random variable X is normally distributed with mean 82 and standard deviation 7.4. Find the value of q such that P(82 − q &l

mezya [45]

P(82 - q < x < 82 + q) = 0.44
P(x < 82 + q) - P(82 - q) = 0.44
P(z < (82 + q - 82)/7.4 - P(z < (82 - q - 82)/7.4) = 0.44
P(z < q/7.4) - P(z < -q/7.4) = 0.44
P(z < q/7.4) - (1 - P(z < q/7.4) = 0.44
P(z < q/7.4) - 1 + P(z < q/7.4) = 0.44
2P(z < q/7.4) - 1 = 0.44
2P(z < q/7.4) = 1.44
P(z < q/7.4) = 0.72
P(z < q/7.4) = P(z < 0.583)
q/7.4 = 0.583
q = 0.583 x 7.4 = 4.31

8 0

2 years ago