Ask question

Ask question

All categories

2 years ago

13

A collector’s item is purchased for $150 and its value increases by 3% each year. Which graph can be used to determine approxima

tely how many years it will take for the value to double?

2 answers:

Tju [1.3M]2 years ago

8 0

The answer is b.

A is in the negatives, and there are no negative years.

B works ; it starts at 150, is positive, and slowly reaches 300

C is exponential and goes to fast.

D starts at 0 not 150

So the answer is b.

Hope this helps!

sveta [45]2 years ago

5 0

Answer:

The answer is B

Step-by-step explanation:

You might be interested in

Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch

enot [183]

Answer:

$y=\frac{-7t^2+22t-7}{7t-22}$

Step-by-step explanation:

We are given that

Initial value problem

$y'=(t+y)^2-1$ , y(3)=4

Substitute the value $z=t+y$

When t=3 and y=4 then

z=3+4=7

$y'=z^2-1$

Differentiate z w.r.t t

Then, we get

$\frac{dz}{dt}=1+y'$

$z'=1+z^2-1=z^2$

$z^{-2}dz=dt$

Integrate on both sides

$-\frac{1}{z}dz=t+C$

$z=-\frac{1}{t+C}$

Substitute t=3 and z=7

Then, we get

$7=-\frac{1}{3+C}$

$21+7C=-1$

$7C=-1-21=-22$

$C=-\frac{22}{7}$

Substitute the value of C then we get

$z=-\frac{1}{t-\frac{22}{7}}$

$z=\frac{-7}{7t-22}$

$y=z-t$

$y=\frac{-7}{7t-22}-t$

$y=\frac{-7-7t^2+22t}{7t-22}$

$y=\frac{-7t^2+22t-7}{7t-22}$

8 0

2 years ago

Would apreciate if someone helped me..

PtichkaEL [24]

Answer:

a). x = 11

b). m∠DMC = 39°

c). m∠MAD = 66°

d). m∠ADM = 36°

e). m∠ADC = 18°

Step-by-step explanation:

a). In the figure attached,

m∠AMC = 3x + 6

and m∠DMC = 6x - 49

Since "in-center" of a triangle is a points where the bisectors of internal angles meet.

Therefore, MC is the angle bisector of angle AMD.

and m∠AMC ≅ m∠DMC

3x + 6 = 8x - 49

8x - 3x = 49 + 6

5x = 55

x = 11

b). m∠DMC = 8x - 49

= (8 × 11) - 49

= 88 - 49

= 39°

c). m∠MAD = 2(m∠DAC)

= 2(30)°

= 60°

d). Since, m∠AMD + m∠ADM + m∠MAD = 180°

2(39)° + m∠ADM + 66° = 180°

78° + m∠ADM + 66° = 180°

m∠ADM = 180° - 144°

= 36°

e). m∠ADC = $\frac{1}{2}(m\angle ADM)$

= $\frac{1}{2}(36)$

= 18°

5 0

2 years ago

Ed is 7 years older than Ted. Ed’s age is also 3/4 times Ted’s age. How old are Ed and Ted?

svetlana [45]

Let Ted be x.

Ed is 7 years older = x + 7

Ed = (3/4)Ted

(x + 7) = (3/4)x

x + 7 = 3x/4

x - 3x/4 = -7

x/4 = -7

x = -28, Ted = -28 years.

(x + 7) = -28 + 7 = -21, Ed = -21 years

Goodness. We had negative numbers for the ages, well does that make sense? No it doesn't.

Our answer is correct. But the sense in the question is lacking. The question has been wrongly set.

<span>We might assume negative ages to mean before they came into the world, before birth! </span>

7 0

2 years ago

Kari is flying a kite. She releases 50 feet of string. What is the approximate difference in the height of the kite when the str

nirvana33 [79]

Sinα=h/L where h=height, L=string length...

h=Lsinα so

h(25°)=50sin25≈21.1ft

h(45°)=50sin45≈35.4ft

5 0

2 years ago

Read 2 more answers

Melissa wants to make a table representing the area of her vegetable garden for a variety of different lengths of the tomato pat

Ksenya-84 [330]

Answer:

$\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\ \ [6.75]&147.25\\7&[51.875]\end{array}$

Step-by-step explanation:

The date from the given table, is expressed as follows;

Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___

Length of Tomato Patch (in feet); ___, 6.5, ___, 7

The length of the tomato patch increases with decrease in the area of the garden

Given that the length of the tomato patch is the independent variable, we can have;

Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7

Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75

Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5

The width of the tomato patch, w = 381.5 ft.

The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;

A = TA - 381.5·l

338 = TA - 381.5×6.25

TA = 338 + 381.5×6.25 = 2,722.375

Therefore, when l = 6.5, we get

A = 2,722.375 - 381.5×6.5 = 242.625

When l = 7, we get

A = 2,722.375 - 381.5×7 = 51.875

Therefore, we get;

$\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\ \ [6.75]&147.25\\7&[51.875]\end{array}$

5 0

1 year ago