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Ray Of Light [21]
1 year ago
9

A large school district is considering moving up the start date for the school year by two weeks. In order to determine if famil

ies would support this, surveys were mailed out to 1000 parents/guardians in the district. The survey said, "We believe that starting school two weeks earlier will be beneficial to the students in our District. Would you support moving up the start date for the school year by two weeks?" The School Board received 492 responses from the survey, 72% of which supported the proposal. -Describe a potential source of bias in the wording of the question. -Due to the bias described in part (a), is the sample proportion of 72% likely greater than or less than the actual proportion of families who support the proposal? Explain. -What type of sample was taken? -Less than half of those sent the letter returned a response. What type of bias is this?
Mathematics
1 answer:
Anvisha [2.4K]1 year ago
5 0

Answer:

(a) Confirmation bias

(b) Likely less than actual proportion of families who support the proposal

(c) Random sample

(d) Nonresponse bias

Step-by-step explanation:

In confirmation bias, the researcher already has and intends to prove an assumption about the effect the of a treatment before carrying out the survey, such that the survey or research is tries to dictate to the participants in the survey about the desired outcome

In the question, the belief of the researcher is expressed to the participants in a form of brief at the start of the survey which is attempting to influence the responses to the survey, such that the actual result should be less than what was observed.

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The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the foll
Mrrafil [7]

Answer

given,

thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

X = U[0.95,1.05]           0.95≤ x ≤ 1.05

the cumulative distribution function of flange

F(x) = P{X≤ x}=\dfrac{x-0.95}{1.05-0.95}

                     =\dfrac{x-0.95}{0.1}

b) P(X>1.02)= 1 - P(X≤1.02)

                   = 1- \dfrac{1.02-0.95}{0.1}

                   = 0.3

c) The thickness greater than 0.96 exceeded by 90% of the flanges.

d) mean = \dfrac{0.95+1.05}{2}

              = 1

   variance = \dfrac{(1.05-0.95)^2}{12}

                  = 0.000833

4 0
2 years ago
Write an expression that can be used to multiply 6 times 198 mentally
Zigmanuir [339]
I would half 198, get
99 and add a 0, this is how you multiply by 5 in your head

198*5 = 990
990 + 200 = 1190 - 2
= 1188

Alternatively we can round 198 to 200: then multiply by 6

200*6 = 1200

Then We subtract the 6 "2's" that we added

1200 - 12 = 1188


The expression for this is:
(6*200) - (6 * 2)
5 0
2 years ago
Which expressions simplify to a rational answer? Select each correct answer. 29√⋅4√ 3√⋅16−−√ 73⋅−√3√ 5√⋅5√
PolarNik [594]

Answer:

The correct options are 1, 3 and 4.

Step-by-step explanation:

We need to find the expressions whose simplified form is a rational number.

Rational number: If a number is defined in the form of p/q where p and q are integers and q≠0, then it is called a rational number.

For example: 0,2, 4.3 etc.

Irrational number: If a number can not defined in the form of p/q, where p and q are integers and q≠0, then it is called an irrational number.

First expression is

2\sqrt{9}\cdot \sqrt{4}=2(3)\cdot (2)\Rightarrow 6\cdot 2=12

12 is a rational number.

Second expression is

\sqrt{3}\cdot \sqrt{16}=\sqrt{3}\cdot 4\Rightarrow 4\sqrt{3}

4\sqrt{3} is an irrational number.

Third expression is

7\sqrt{3}\cdot \sqrt{3}\Rightarrow 7\cdot 3=21

21 is a rational number.

Fourth expression is

\sqrt{5}\cdot \sqrt{5}=5

5 is a rational number.

Therefore, the correct options are 1, 3 and 4.

4 0
2 years ago
The figure shows a map of five streets that meet at Concord Circle. The measure of the angle formed by Melville Road and Emerson
DiKsa [7]
Do you have a picture?
4 0
2 years ago
Read 2 more answers
A) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.
Fed [463]

Answer:

A) a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

B) a_{0} = a_{1} = 0

C)   for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

Step-by-step explanation:

A) A recurrence relation for the number of bit strings of length n that contain a  pair of consecutive Os can be represented below

if a string (n ) ends with 00 for n-2 positions there are a pair of  consecutive Os therefore there will be : 2^{n-2} strings

therefore for n ≥ 2

The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

b ) The initial conditions

The initial conditions are : a_{0} = a_{1} = 0

C) The number of bit strings of length seven containing two consecutive 0s

here we apply the re occurrence relation and the initial conditions

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

7 0
2 years ago
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