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1 year ago

12

a homeowner plans to hang wallpaper on one wall of a bedroom that is 10 feet long. if a strip of wallpaper is 20 inches wide and

strips are hung vertically, how many strips of wallpaper will the homeowner require?

1 answer:

love history [14]1 year ago

4 0

1 ft = 12 inches....so 10 ft = (10 * 12) = 120 inches

each strip of wall paper is 20 inches...

so 120/20 = 6 strips of wall paper are required <==

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If two different people are randomly selected from the 884 subjects, find the probability that they are both women. Round to fou

galina1969 [7]

The answer is 0.3274

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1 year ago

An inspector checks 98 cell phones and finds that 2 of them are defective. A company has 850 of these phones. How many of the co

jekas [21]

Answer:

17

Step-by-step explanation:

As 2 phones are defective from a group of 98 that were checked, you can determine a percentage:

2/98= 2%

This indicates that 2% of the phones are likely to be defective and because of that you can find 2% of 850:

850*2%= 17

According to this, 17 phones are likely to be defective.

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2 years ago

Adam is using the equation (x)(x + 2) = 255 to find two consecutive odd integers with a product of 255. When Adam solves the pro

kondaur [170]

$\bf (x)(x+2)=255\implies x^2+2x=255\implies x^2+2x-255=y
\\\\
\textit{setting y=0}\implies x^2+2x-255=0
\\\\
\textit{now, factoring that}
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(x+17)(x-15)=0\implies 
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x=-17\\
x=15
\end{cases}$

notice the picture of the graph added here
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the graph is touching the x-axis, an x-intercept
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3 0

1 year ago

Read 2 more answers

The formula P = 0.68x2 - 0.048x + 1 models the approximate population P, in thousands, for a species of fish in a local pond, x

marshall27 [118]

Answer:

The answer to your question is 2184

Step-by-step explanation:

Data

Equation P(x) = 0.68x² - 0.048x + 1

x = years

population = 33984

Process

1.- Substitute the population in the equation

33984 = 0.84x² - 0.048x + 1

2.- Equal to zero

0.84x² - 0.048x + 1 - 33984 = 0

3.- Simplify

0.84x² - 0.048x - 33983 = 0

4.- Solve for x

$x = \frac{0.048 +- \sqrt{(0.048^{2}) - (4)(0.84)(-33982)}}{2(0.84)}$

$x = \frac{0.048 +- \sqrt{337.9}}{1.68}$

x1 = 201.2

x2 = -201.2

Only x1 is correct because time can not be negative

5.- Calculate the year

Year = 1997 + 201

Year = 2184

8 0

1 year ago

Two professors are applying for grants. Professor Jane has a probability of 0.61 of being funded. Professor Joe has probability

Anna11 [10]

Answer:

a. 0.1647;
b. 0.7153;
c. 0.4453.

Step-by-step explanation:

By definition, if two event $A$ and $B$ are independent, then

$P(A\cap B) = P(A) \cdot P(B)$ . ( $P(A\cap B)$ is the probability that the outcome of both event $A$ and event $B$ are true.)

<h3>a.</h3>

Since the outcome of these two events are independent,

$\begin{aligned}P(\texttt{Jane} \cap \texttt{Joe}) &= P(\texttt{Jane}) \cdot P(\texttt{Joe})\\ &= 0.61 \times 0.27 \\&= 0.1647\end{aligned}$ .

<h3>b.</h3>

The logic not operator $\lnot$ or the prime superscript $^{\prime}$ denotes that an event does not happen.

$P(\texttt{Jane}^{\prime}) = 1 - P(\texttt{Jane}) = 1- 0.61 = 0.39$ .

$P(\texttt{Joe}^{\prime}) = 1 - P(\texttt{Joe}) = 1- 0.27 = 0.73$ .

Since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}^{\prime}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that neither professor got funded:

$P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = P(\texttt{Jane}^{\prime}) \cdot P(\texttt{Joe}^{\prime}) = 0.39 \times 0.73 = 0.2847$ .

Probability that at least one professor got funded- in other words, it is not true that neither professor got funded:

$P((\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime})^{\prime}) = 1- P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = 0.7153$ .

<h3>c.</h3>

Similarly, since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that Jane but not Joe got funded:

$P(\texttt{Jane} \cap (\texttt{Joe}^{\prime})) = P(\texttt{Jane}) \cdot P(\texttt{Joe}^{\prime}) = 0.61 \times 0.73 = 0.4453$ .

4 0

1 year ago