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marusya05 [52]
1 year ago
12

a homeowner plans to hang wallpaper on one wall of a bedroom that is 10 feet long. if a strip of wallpaper is 20 inches wide and

strips are hung vertically, how many strips of wallpaper will the homeowner require?
Mathematics
1 answer:
love history [14]1 year ago
4 0
1 ft = 12 inches....so 10 ft = (10 * 12) = 120 inches

each strip of wall paper is 20 inches...

so 120/20 = 6 strips of wall paper are required <==


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James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
2 years ago
julie jot 21 of the 23 questions of her math test correct she got 29 of the 32 questions on her science test correct on which te
Alenkasestr [34]
Make\ a\ common\ denominator:\\\\\frac{21}{23}\ \ \ \ \ \ \ \ \frac{29}{32}\\\\\frac{21\cdot32}{23\cdot32}\ \ \ \ \ \ \ \frac{29\cdot23}{32\cdot23}\\\\\frac{672}{736}\ \ \ > \ \ \ \frac{667}{736}
5 0
1 year ago
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Yuliya22 [10]
First, you need to put them in order
53kg, 55kg, 61kg, 61kg, 76kg, 91kg, 98kg, 105kg, 120kg

For mean, you add them all up and divide by the amount of numbers (9)
720/9 = 80

For median, you find the middle number (76kg)

For mode, you find the number that appears the most (61kg)

Mean: 80
Median: 76
Mode: 61
5 0
1 year ago
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The measure of ADB is 162 . what is the measure of EAB?
Xelga [282]
An angle formed by a chord and a tangent line is half the measure of the intercepted arc.

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The answer is 81 degrees.

6 0
2 years ago
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faust18 [17]

Answer:

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The player has already batted 134 times and will still bat 46 times. So in the end of the year, he is going to have 134 + 46 = 180 at bats.

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This is 40% of 180, which is 0.4*180 = 72.

He has already 39 hits, so in his next 46 at bats, he will need 72 - 39 = 33 hits.

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