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Novosadov [1.4K]
1 year ago
12

Which of these is longest distance 0.1203km or 123m or 1230cm or 12030mm

Mathematics
1 answer:
bogdanovich [222]1 year ago
7 0
<h3>Answer: 123 meters is the longest </h3>

============================

Work Shown:

Convert everything to the same unit. I'm going to convert everything to meters

0.1203 km = 120.3 meters (multiply by 1000)

1230 cm = 12.3 meters (divide by 100)

12030 mm = 12.03 meters (divide by 1000)

------------------

The four distances we have are: 120.3 meters, 123 meters, 12.3 meters, 12.03 meters. We see that 123 meters is the longest.

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JulsSmile [24]

(1) x represents the number of apples bought, y represents the number of bananas.

(2) each term represents the total costs of a given fruit, so 0.50x is the total cost of apples and 0.30y is total cost of bananas.

(3) The coefficients are unit prices: coefficient 0.50 is the price of 1 apple, 0.30 is the price of 1 banana.

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1 year ago
A company purchased a delivery van for $28,000 with a salvage value of $3,000 on September 1, Year 1. It has an estimated useful
Tems11 [23]

Answer:

Depreciation till December 31, Year 1 will be equal to 1,250$

Step-by-step explanation:

Purchasing Cost = 28,000$

Salvage Value = 3,000$

Total Depreciation:

Total Depreciation over 5 years (60 Months) = Purchasing Cost - Salvage Value

Total Depreciation over 5 years (60 Months) = 28,000 - 3,000

Total Depreciation over 5 years (60 Months) = 25,000$

Monthly Depreciation:

Using the unity method we have monthly depreciation by dividing the total depreciation by the total no. of months as below:

Total Depreciation over a single month =25,000/60

Total Depreciation over a single month = 416.67$ (Monthly Depreciation)

Depreciation till December 31, Year 1

As from September 1, Year 1 to December 31, Year 1, its been 3 months therefore total depreciation will be = 3 * Monthly Depreciation

Depreciation till December 31, Year 1 = 3 * 416.67

Depreciation till December 31, Year 1 = 1,250$

4 0
1 year ago
Cylinder A has a volume of 360 cm3. Cylinder B has a base and height identical to that of the cylinder B, but it is the right in
yaroslaw [1]

Answer:

Answer:

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Step-by-step explanation:

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3 0
2 years ago
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Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of s
Elenna [48]

I will rewrite the question for better understanding:

Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of samples in her neighborhood. It takes Ashley 2/3 of a minute to prepare one bag. It takes each of her friends 75% longer to prepare a bag. How many hours will it take Ashley and 4 of her friends to prepare 1575 bags of samples?

Answer:

  • <em><u>5.3 hours</u></em>

Explanation:

<u>1) Time it takes Ashley to preprate one bag: </u>

  • 2/3 min

<u>2) Time it takes each friend of Ashley: 75% more than 2/3 min</u>

  • 75% × 2/3 min = 0.75 × 2/3 min = 3/4 × 2/3 min= 2/4 min = 1/2 min = 0.5 min
  • 2/3 min + 1/2 min = 7/6 min

<u>3) Time it takes Ashley and the 4 friends working along to prepare one bag:</u>

  • Convert each time into a rate, since you can set that the total rate of Ashley along with her four friends is equal to the sum of each rate:

  • Rate of Ashley: 1 bag / (2/3) min = 3/2 bag/min

  • Rate of each friend: 1 bag / (7/6) min = 6/7 bag/min

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<u>4) Time of prepare 1575 bags of samples:</u>

  • time = number of bags / number of bags per min = 1,575 bags / (69/14) bags/min = 319.56 min

<u>5) Convert minutes to hours:</u>

  • 356.56 min × 1 hour / 60 min = 5.3 hours
3 0
1 year ago
An aquarium has a base in the shape of a trapezoid. The base is 90 cm long at the front, 60 cm long at the back, and 30 cm wide
Nonamiya [84]

Answer:

Step-by-step explanation:

First calculate for the area of the trapezoid (the formula is (base + base / 2) x height):

60 cm + 90 cm = 150 cm

150 cm / 2 = 75 cm

75 cm x 30 cm = 2250 cm²

Now 1 cm² = 1 mL and 1000 mL = 1 L

2250 cm² = 2250 mL

2250 mL = 2.25 L

5 0
1 year ago
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